int byte to string in java

Question

Problem

I read first byte in my socket client to check connection:

ByteBuffer b = ByteBuffer.allocate(4);
b.order(ByteOrder.BIG_ENDIAN);
...
int dataInt = clientSocket.getInputStream().read();

Documentation:

Reads a single byte from this stream and returns it as an integer in the range from 0 to 255. Returns -1 if the end of the stream has been reached.

after that I want to splice this byte with next input string. I convert this integer byte to characters

b.putInt(dataInt);
byte[] dataByte = b.array();
final String data;

and check it. If dataInt != -1, I have to return this croped byte into new string:

if(dataInt != -1)
{
    String c = new String(dataByte);
    Log.v("MSG", c);
    data = c + inToServer.readLine();
}
else
{
    data = inToServer.readLine();
}

Why I see in log "MSG, ��MY MESSAGE"? How to get a string correctly?

Upd, how I send my messages:

byte[] buf = str.getBytes("UTF-8");
outToServer.write(buf, 0, buf.length);
outToServer.writeBytes("\n");
outToServer.flush();

In Java, characters are represented as two bytes. Although your file may or may not be storing them as 1 or 2. Something to consider. Maybe your b allocation should be 1 or 2, not 4. — IAmGroot
– IAmGroot, Commented Nov 11, 2012 at 20:25
How are your characters stored? as 4 byte integer values of a char? If this is the case, you shouldnt be creating a string from the byte array directly, but casting the int value to char. — IAmGroot
– IAmGroot, Commented Nov 11, 2012 at 20:32

gordy · Accepted Answer · 2012-11-11 20:40:33Z

2

if(dataInt != -1)
{
    String c = new String(dataByte, "UTF-8");
    Log.v("MSG", c);
    data = c + inToServer.readLine();
}
else
{
    data = inToServer.readLine();
}

answered Nov 11, 2012 at 20:40

gordy

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4 Comments

Leo Over a year ago

No, it does not work. V/data(30887): ��msg#Leo#kokoko E/AndroidRuntime(30887): FATAL EXCEPTION: main

IAmGroot Over a year ago

@Leo His answer looks pretty solid to me. +1 for more in-depth. Are you sure the byte array you recieved is complete. And not anything additional. Send a small string, and see what numbrs are in the array, before and after.

gordy Over a year ago

Perhaps try new String(dataByte, "ISO-8859-1"); so you can at least see what bytes are coming back instead of the invalid unicode character ?'s

Leo Over a year ago

@Doomsknight Yes, I'm sure cause if I dont use clientSocket.getInputStream().read(), all my messages is complete. But so I cant't see my socket state.

IAmGroot · Accepted Answer · 2012-11-11 20:40:55Z

1

Okay, so on your server side just do this with your recieved byte[] There is no need for byte buffers, or to manipulate it in any way.

String str = new String(recievedBytes);

answered Nov 11, 2012 at 20:40

IAmGroot

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1 Comment

IAmGroot Over a year ago

@Leo remove your byte buffer stuff, and read it directly into the new String(recievedBytes); method.

Community · Accepted Answer · 2017-05-23 11:56:11Z

0

I would recommend you to use IOUtils.toString for this. It facilitates a lot of the boring and error prone input/output stream manipulation.

Here is an answer explaining how to setup your project to use apache IO commons.

edited May 23, 2017 at 11:56

CommunityBot

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answered Nov 11, 2012 at 20:48

renam.antunes

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Comments

Leo · Accepted Answer · 2012-11-11 21:16:58Z

0

Omg, I did it. Solution:

byte[] b1 = new byte[1];
int dataInt = clientSocket.getInputStream().read();
b1[0] = (byte)dataInt;

answered Nov 11, 2012 at 21:16

Leo

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