Find two numbers in string with Ruby using Regex

Question

I have a string that looks like this:

Results 1 - 10 of 20

How would I find the number 10 and 20 of that sentence using regex in Ruby?

Something like:

first_number, second_number = compute_regex(my_string)...

Thanks

Cris Stringfellow · Accepted Answer · 2013-03-14 16:16:41Z

1

Like so:

first, second = *source.scan(/\d+/)[-2,2]

Explanation

\d+ matches any number

scan finds all matches of its regular expression argument in source

[-2,2] returns the last two numbers in an array: starts at index -2 from end, returns next 2

* splat operator unpacks these two matches into the variables first and second (NOTE: this operator is not necessary, you can remove this, and I like the concept)

edited Mar 14, 2013 at 16:16

answered Mar 14, 2013 at 16:11

Cris Stringfellow

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1 Comment

Dave S. Over a year ago

The splat isn't strictly necessary is it?

Dave S. · Accepted Answer · 2013-03-14 16:10:37Z

0

Try this:

a = "Results 1 - 10 of 20"
first_number, second_number = a.match(/\w+ (\d) \- (\d+) of (\d+)/)[2..3].map(&:to_i)

The map piece is necessary because the regexp MatchData objects returned are strings.

answered Mar 14, 2013 at 16:10

Dave S.

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