If I have a string like
6d7411014f
I want to read the the occurrence of first two integers and put the final number in a variable
Based on above example my variable would contain 67
more examples:
d550dfe10a
variable would be 55
What i've tried is \d but that gives me 6. how do I get the second number?
I'd use scan for this sort of thing:
n = my_string.scan(/\d/)[0,2].join.to_i
You'd have to decide what you want to do if there aren't two numbers though.
For example:
>> '6d7411014f'.scan(/\d/)[0,2].join.to_i
=> 67
>> 'd550dfe10a'.scan(/\d/)[0,2].join.to_i
=> 55
>> 'pancakes'.scan(/\d/)[0,2].join.to_i
=> 0
>> '6 pancakes'.scan(/\d/)[0,2].join.to_i
=> 6
References:
I really can't answer this exactly in Ruby, but a regex to do it is:
/^\D*(\d)\D*(\d)/
Then you have to concatenate $1 and $2 (or whatever they are called in Ruby).
my_string.match(/^\D*(\d)\D*(\d)/).captures.join. This will return the string representation of the two first digits in my_string.Building off of sidyll's answer,
string = '6d7411014f'
matched_vals = string.match(/^\D*(\d)\D*(\d)/)
extracted_val = matched_vals[1].to_i * 10 + matched_vals[2].to_i
