Convert string to JSON array

Question

I have the following string of a JSON from a web service and am trying to convert this to a JSONarray

{
    "locations": [
        {
            "lat": "23.053",
            "long": "72.629",
            "location": "ABC",
            "address": "DEF",
            "city": "Ahmedabad",
            "state": "Gujrat",
            "phonenumber": "1234567"
        },
        {
            "lat": "23.053",
            "long": "72.629",
            "location": "ABC",
            "address": "DEF",
            "city": "Ahmedabad",
            "state": "Gujrat",
            "phonenumber": "1234567"
        },
        {
            "lat": "23.053",
            "long": "72.629",
            "location": "ABC",
            "address": "DEF",
            "city": "Ahmedabad",
            "state": "Gujrat",
            "phonenumber": "1234567"
        },
        {
            "lat": "23.053",
            "long": "72.629",
            "location": "ABC",
            "address": "DEF",
            "city": "Ahmedabad",
            "state": "Gujrat",
            "phonenumber": "1234567"
        },
        {
            "lat": "23.053",
            "long": "72.629",
            "location": "ABC",
            "address": "DEF",
            "city": "Ahmedabad",
            "state": "Gujrat",
            "phonenumber": "1234567"
        }
    ]
}

I validated this String online, it seems to be correct. Now I am using the following code in android development to utilise

JSONArray jsonArray = new JSONArray(readlocationFeed);

This throws exception a type mismatch Exception.

What data type is readlocationFeed?

IgorGanapolsky
– IgorGanapolsky

2016-03-23 18:21:11 +00:00
Commented Mar 23, 2016 at 18:21 — IgorGanapolsky
– IgorGanapolsky, Commented Mar 23, 2016 at 18:21
@IgorGanapolsky, String

Andrew No
– Andrew No

2016-04-20 17:54:48 +00:00
Commented Apr 20, 2016 at 17:54 — Andrew No
– Andrew No, Commented Apr 20, 2016 at 17:54

Alireza Noorali · Accepted Answer · 2018-11-21 08:53:01Z

220

Here you get JSONObject so change this line:

JSONArray jsonArray = new JSONArray(readlocationFeed);

with following:

JSONObject jsnobject = new JSONObject(readlocationFeed);

and after

JSONArray jsonArray = jsnobject.getJSONArray("locations");
for (int i = 0; i < jsonArray.length(); i++) {
    JSONObject explrObject = jsonArray.getJSONObject(i);
}

edited Nov 21, 2018 at 8:53

Alireza Noorali

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answered Mar 25, 2013 at 7:01

kyogs

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2 Comments

ankitkpd Over a year ago

noticed that constructor for JSONObject looks outdated and does not support String as a parameter in version 1.1.1

DragonFire Over a year ago

jsnobject could be jsonobject - spelling :)

partho · Accepted Answer · 2017-09-14 15:04:03Z

56

Input String

[
   {
      "userName": "sandeep",
      "age": 30
   }, 
   {
      "userName": "vivan",
      "age": 5
   }
]

Simple Way to Convert String to JSON

public class Test
{

    public static void main(String[] args) throws JSONException
    {
        String data = "[{\"userName\": \"sandeep\",\"age\":30},{\"userName\": \"vivan\",\"age\":5}]  ";
        JSONArray jsonArr = new JSONArray(data);

        for (int i = 0; i < jsonArr.length(); i++)
        {
            JSONObject jsonObj = jsonArr.getJSONObject(i);

            System.out.println(jsonObj);
        }

    }
}

Output

{"userName":"sandeep","age":30}
{"userName":"vivan","age":5}

edited Sep 14, 2017 at 15:04

partho

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answered Oct 24, 2015 at 7:46

Sandeep Bhardwaj

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Comments

Aravind Cheekkallur · Accepted Answer · 2015-05-04 08:24:12Z

30

Using json lib:-

String data="[{"A":"a","B":"b","C":"c","D":"d","E":"e","F":"f","G":"g"}]";
Object object=null;
JSONArray arrayObj=null;
JSONParser jsonParser=new JSONParser();
object=jsonParser.parse(data);
arrayObj=(JSONArray) object;
System.out.println("Json object :: "+arrayObj);

Using GSON lib:-

Gson gson = new Gson();
String data="[{\"A\":\"a\",\"B\":\"b\",\"C\":\"c\",\"D\":\"d\",\"E\":\"e\",\"F\":\"f\",\"G\":\"g\"}]";
JsonParser jsonParser = new JsonParser();
JsonArray jsonArray = (JsonArray) jsonParser.parse(data);

edited May 4, 2015 at 8:24

answered Oct 29, 2013 at 11:31

Aravind Cheekkallur

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5 Comments

PAA Over a year ago

This will not be worked for Google GSON? Could you help for thhis?

Aravind Cheekkallur Over a year ago

@pashtika.. please explain with your problem..then i can try for that.

Aravind Cheekkallur Over a year ago

@pashtika ..yes you can use the GSON jar and convert your string into json

Dev-iL Over a year ago

There seems to be a mistake in the 2nd code snippet, since the gson object is created but not used.

fritz-playmaker Over a year ago

Just ignore the first line. It works with out it Gson gson = new Gson();

ρяσѕρєя K · Accepted Answer · 2013-03-25 07:05:28Z

19

you will need to convert given string to JSONObject instead of JSONArray because current String contain JsonObject as root element instead of JsonArray :

JSONObject jsonObject = new JSONObject(readlocationFeed);

edited Mar 25, 2013 at 7:05

answered Mar 25, 2013 at 7:00

ρяσѕρєя K

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Comments

Furqi · Accepted Answer · 2013-03-25 07:04:26Z

6

String b = "[" + readlocationFeed + "]";
JSONArray jsonArray1 = new JSONArray(b);
jsonarray_length1 = jsonArray1.length();
for (int i = 0; i < jsonarray_length1; i++) {

}

or convert it in JSONOBJECT

JSONObject jsonobj = new JSONObject(readlocationFeed);
JSONArray jsonArray = jsonobj.getJSONArray("locations");

answered Mar 25, 2013 at 7:04

Furqi

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1 Comment

DragonFire Over a year ago

string manipulation is a great way of thinking from another direction - regarding this problem

Bunyamin Coskuner · Accepted Answer · 2018-11-21 10:47:37Z

4

Try this piece of code:

try {        
    Log.e("log_tag", "Error in convert String" + result.toString());
    JSONObject json_data = new JSONObject(result);

    String status = json_data.getString("Status");
    {
        String data = json_data.getString("locations");
        JSONArray json_data1 = new JSONArray(data);
        for (int i = 0; i < json_data1.length(); i++) {
            json_data = json_data1.getJSONObject(i);

            String lat = json_data.getString("lat");
            String lng = json_data.getString("long");
        }
    }
}

edited Nov 21, 2018 at 10:47

Bunyamin Coskuner

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answered Mar 25, 2013 at 7:00

Nirav Ranpara

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Comments

Sanu · Accepted Answer · 2014-03-04 06:57:19Z

3

if the response is like this

"GetDataResult": "[{\"UserID\":1,\"DeviceID\":\"d1254\",\"MobileNO\":\"056688\",\"Pak1\":true,\"pak2\":true,\"pak3\":false,\"pak4\":true,\"pak5\":true,\"pak6\":false,\"pak7\":false,\"pak8\":true,\"pak9\":false,\"pak10\":true,\"pak11\":false,\"pak12\":false}]"

you can parse like this

JSONObject jobj=new JSONObject(response);
        String c = jobj.getString("GetDataResult");         
        JSONArray jArray = new JSONArray(c);
        deviceId=jArray.getJSONObject(0).getString("DeviceID");

here the JsonArray size is 1.Otherwise you should use for loop for getting values.

answered Mar 4, 2014 at 6:57

Sanu

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Comments

Alireza Noorali · Accepted Answer · 2018-11-21 11:24:15Z

It's a very simple way to convert:

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import com.google.gson.Gson;
import com.google.gson.JsonArray;
import com.google.gson.JsonElement;
import com.google.gson.JsonParser;


class Usuario {
private String username;
private String email;
private Integer credits;
private String twitter_username;

public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

public String getEmail() {
    return email;
}

public void setEmail(String email) {
    this.email = email;
}

public Integer getCredits() {
    return credits;
}

public void setCredits(Integer credits) {
    this.credits = credits;
}

public String getTwitter_username() {
    return twitter_username;
}

public void setTwitter_username(String twitter_username) {
    this.twitter_username = twitter_username;
}

@Override
public String toString() {
    return "UserName: " + this.getUsername() + " Email: " + this.getEmail();
}

}

/*
 * put string into file jsonFileArr.json
 * [{"username":"Hello","email":"[email protected]","credits"
 * :"100","twitter_username":""},
 * {"username":"Goodbye","email":"[email protected]"
 * ,"credits":"0","twitter_username":""},
 * {"username":"mlsilva","email":"[email protected]"
 * ,"credits":"524","twitter_username":""},
 * {"username":"fsouza","email":"[email protected]"
 * ,"credits":"1052","twitter_username":""}]
 */

public class TestaGsonLista {

public static void main(String[] args) {
    Gson gson = new Gson();
    try {
        BufferedReader br = new BufferedReader(new FileReader(
                "C:\\Temp\\jsonFileArr.json"));
        JsonArray jsonArray = new JsonParser().parse(br).getAsJsonArray();
        for (int i = 0; i < jsonArray.size(); i++) {
            JsonElement str = jsonArray.get(i);
            Usuario obj = gson.fromJson(str, Usuario.class);
            System.out.println(obj);
            System.out.println(str);
            System.out.println("-------");
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
}

}

Please improve you answer by adding context as text and not a comment.

Jonathan Nolasco Barrientos · Accepted Answer · 2014-10-03 18:57:59Z

1

You can do the following:

JSONArray jsonArray = jsnobject.getJSONArray("locations");
    for (int i = 0; i < jsonArray.length(); i++) {
        JSONObject explrObject = jsonArray.getJSONObject(i);
}

answered Oct 3, 2014 at 18:57

Jonathan Nolasco Barrientos

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Comments

Harshit Gupta · Accepted Answer · 2024-02-21 07:08:40Z

1

If using org.json.simple library to handle JSON in your project then -

String response = "[{\"UserID\":1,\"DeviceID\":\"d1254\",\"MobileNO\":\"056688\",\"Pak1\":true,\"pak2\":true,\"pak3\":false,\"pak4\":true,\"pak5\":true,\"pak6\":false,\"pak7\":false,\"pak8\":true,\"pak9\":false,\"pak10\":true,\"pak11\":false,\"pak12\":false}]";
    try {
         JSONArray responseArray = (JSONArray) new JSONParser().parse(response);
         // Do further processing/parsing of responseArray 
    } catch (ParseException | ClassCastException e) {
        // Handle JSON parsing exception
        System.out.println("Error parsing response JSON: " + e.getMessage());
    }

answered Feb 21, 2024 at 7:08

Harshit Gupta

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Comments

abhishek ringsia · Accepted Answer · 2014-09-26 14:20:30Z

If having following JSON from web service, Json Array as a response :

       [3]
 0:  {
 id: 2
 name: "a561137"
 password: "test"
 firstName: "abhishek"
 lastName: "ringsia"
 organization: "bbb"
    }-
1:  {
 id: 3
 name: "a561023"
 password: "hello"
 firstName: "hello"
  lastName: "hello"
  organization: "hello"
 }-
 2:  {
  id: 4
  name: "a541234"
  password: "hello"
  firstName: "hello"
  lastName: "hello"
  organization: "hello"
    }

have To Accept it first as a Json Array ,then while reading its Object have to use Object Mapper.readValue ,because Json Object Still in String .

      List<User> list = new ArrayList<User>();
      JSONArray jsonArr = new JSONArray(response);


      for (int i = 0; i < jsonArr.length(); i++) {
        JSONObject jsonObj = jsonArr.getJSONObject(i);
         ObjectMapper mapper = new ObjectMapper();
        User usr = mapper.readValue(jsonObj.toString(), User.class);      
        list.add(usr);

    }

mapper.read is correct function ,if u use mapper.convert(param,param) . It will give u error .

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