Here's my problem, I'd like to have a string that would define my function parameters like this :
function blabla($param1, $param2){
my cool code . $param1 . $param2;
}
$params = 'param1, param2';
blabla($params);
The problem is that when I do this, he uses the string 'param1, param2' as ONE arguments instead of TWO like i'd want 2
That's a very backwards thing to want to do, but you'd probably do it by exploding your string into an array of values, and using call_user_func_array to pass those values as the parameters to the function.
function blah($x, $y) {
echo "x: $x, y: $x";
}
$xy = "4, 5";
$params = explode(", ", $xy);
# Just like calling blah("4", "5");
call_user_func_array('blah', $params);
I'll warn you again however that you've probably chosen the wrong solution to whatever your problem is.
How you are wanting to do it, you can't. However, look in to call_user_func_array as it may solve what you are trying to do. Demonstration follows:
function blabla($param1, $param2){
echo "my cool code $param1 $param2";
}
$params = 'does,work';
call_user_func_array('blabla', explode(',', $params));
use explode() php function
function blabla($param){
$params = explode(',', $param);
$param1 = $params[0];
$param2 = $params[1];
}
$params = 'param1, param2';
blabla($params);
PHP is interpreting this as one argument because you have specified a single string, which just happens to include a comma; just something to bear in mind for the future.
Something very simple is:
function blabla($param1, $param2){
my_cool_code . $param1 . $param2;
}
blabla($param1, $param2);
First, a function name must not have a '$'. Secondly, you have only 2 params, you can pass both params through the function, like above.
The code is now good to use :)
