How to use a php variable within a define function

Question

I'm trying to add a name into a defined filepath like this -

define("theme_name", "andrew");
define("LAYOUT_DIR", ROOT_DIR.'_content/layouts/themes/<?php echo $theme_name;?>/');

I get an error that the path does not exist when it is executed but the "andrew" folder does exist.

I tried joining with dots instead of echo and still got this error.

Full error message

Fatal error: Uncaught exception 'Twig_Error_Loader' with message 'The "G:\Uwamp\www\lightbulb_edison/../_content/layouts/themes/ . $theme_name . /" directory does not exist.' ````

echo is not meant for joining variables. And <?php is pointless within a string or expression. And your theme_name is a constant too, not a variable. — mario
– mario, Commented Feb 2, 2016 at 4:13

Amit Rajput · Accepted Answer · 2016-02-02 04:26:15Z

3

You can use (.) for concatenation in php . like below..

define("theme_name", "andrew");
define("LAYOUT_DIR", ROOT_DIR.'_content/layouts/themes/'.theme_name.'/');

Or you can do this by using variable like this..

define("theme_name", "andrew");
$theme_name = theme_name;
define("LAYOUT_DIR", ROOT_DIR.'_content/layouts/themes/'.$theme_name.'/');

edited Feb 2, 2016 at 4:26

answered Feb 2, 2016 at 4:20

Amit Rajput

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Jagadeesh · Accepted Answer · 2016-02-02 04:28:38Z

2

In php the concatenation operator is DOT(.)

If you define a variable in php like following

define("theme_name", "andrew");

Then you have to use the variable like below

define("LAYOUT_DIR", ROOT_DIR. '_content/layouts/themes/'. theme_name . '/');

answered Feb 2, 2016 at 4:28

Jagadeesh

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