I want to write a bash script that will get user input and store it in an array. Input: 1 4 6 9 11 17 22
I want this to be saved as array.
4
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1you don't neeed an array to loop over the values.Karoly Horvath– Karoly Horvath2013-06-19 19:31:50 +00:00Commented Jun 19, 2013 at 19:31
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I Dont want to run a dynamic loop. the input will be used in further loops in the code.Vignesh– Vignesh2013-06-19 19:35:23 +00:00Commented Jun 19, 2013 at 19:35
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as long as you don't need random access (indexing), there's no reason to use arrays.Karoly Horvath– Karoly Horvath2013-06-19 19:36:39 +00:00Commented Jun 19, 2013 at 19:36
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how can i just save it in an array?Vignesh– Vignesh2013-06-19 19:37:53 +00:00Commented Jun 19, 2013 at 19:37
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3 Answers
read it like this:
read -a arr
Test:
read -a arr <<< "1 4 6 9 11 17 22"
print # of elements in array:
echo ${#arr[@]}
OR loop through the above array
for i in ${arr[@]}
do
echo $i # or do whatever with individual element of the array
done
3 Comments
Vignesh
@anubhava: can u explain why there is an @? Now i get the unexpected token error. I think the for brackets are not balanced
anubhava
can you try quotes:
for i in "${arr[@]}"anubhava
Here's my 2 cents.
#!/bin/sh
read -p "Enter server names separated by 'space' : " input
for i in ${input[@]}
do
echo ""
echo "User entered value :"$i # or do whatever with individual element of the array
echo ""
done
Comments
How about this:
while read line
do
my_array=("${my_array[@]}" $line)
done
printf -- 'data%s ' "${my_array[@]}"
Hit Ctrl-D to stop entering numbers.
1 Comment
chepner
my_array+=( $line ) would be much simpler.