Read multiple inputs and store in a array, then print the values from that array in shell script

Question

Read multiple inputs then store that in an array or variables, then print the values from that array/variables in shell script

read -p " Enter no. of users : " no_user
            if [ $no_user -gt 1 ]; then
                for ((i=1;; i++)); do
                    read -p "Enter Mob no ($i) : " $[mob$i]
                    if [ $i == $no_user ]; then break; fi
                done
            else
                read -p "Enter Mob no ($i) : " mob$i
            fi
                if [ $no_user > 1 ]; then
                    for ((i=1;; i++)); do
                        echo "Mobile no $i = " $[mob$i]
                            if [ $i == $no_user ]; then break; fi
                    done
                fi

Using a loop that just reads users until a sentinel/blank line is read instead of asking for a count is probably a friendlier model. — Etan Reisner
– Etan Reisner, Commented Apr 30, 2015 at 13:04

Jahid · Accepted Answer · 2015-04-30 17:18:10Z

2

Change $[mob$i] and mob$i to mob[$i] at line 5 and 9. And also change $[mob$i] to ${mob[$i]} at line 13

Complete code:

read -p " Enter no. of users : " no_user
if [ $no_user -gt 1 ]; then
for ((i=1;; i++)); do
read -p "Enter Mob no ($i) : " mob[$i]
if [ $i == $no_user ]; then break; fi
done
else
read -p "Enter Mob no ($i) : " mob[$i]
fi
if [ $no_user > 1 ]; then
for ((i=1;; i++)); do
echo "Mobile no $i = " ${mob[$i]}
if [ $i == $no_user ]; then break; fi
done
fi

answered Apr 30, 2015 at 17:18

Jahid

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Comments

Vadim Landa · Accepted Answer · 2015-04-30 12:58:57Z

1

Using mob$i instead of $[mob$i] on line 4 will fix your problem.

answered Apr 30, 2015 at 12:58

Vadim Landa

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