Modify bash arguments and pass to java program

Question

Is it possible to modify the arguments passed to a bash program ? and then pass them to a Java program ?

I know we can access all the arguments passed to a bash program by "$@" and I can pass them to Java program like java com.myserver.Program "$@". But is it possible to modify value of certain arguments inside "$@" and then call the above java program with "$@" ?

I also know you can use "$@[1]" to access the value of arguments but how can we iterate over them and change the value at the proper position ? I also know this :

for arg
do
....
done

But inside the do loop how can the value of argument be modified and then java program be called ?

konsolebox · Accepted Answer · 2013-09-15 16:29:55Z

4

Iterate through every item in the positional parameters, then add them to another array, modifying it if needed while you do.

ARGS=()
for A in "$@"; do
    # Modify A then add it to args. 
    # A=${A//something/something} ## Just an example.
    ARGS+=("$A")
done

# Then call java:

java com.myserver.Program "${ARGS[@]}"

And since you're processing positional parameters, it would be simpler to use this form of for:

for A; do

edited Sep 15, 2013 at 16:29

answered Sep 15, 2013 at 16:24

konsolebox

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3 Comments

Anuj Kulkarni Over a year ago

I was thinking of doing this : stackoverflow.com/a/3156914/1291961. But how can I pass that as argument to Java class?

konsolebox Over a year ago

@WarriorPrince On my example it's java com.myserver.Program "${ARGS[@]}".

Anuj Kulkarni Over a year ago

Yes Just saw the edit. Awesome it worked. Thank you very much for detailed explanation.

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