Linux shell script for calling Java program with arguments

Question

I have a java program that runs as a service in linux box. I have shell script file that has the following line to start the program.

$EXEC -home "$JAVA_HOME" -cp "$CLASS_PATH" -outfile "$LOG_OUT" -errfile "$LOG_ERR" -pidfile "$PID" $1 $CLASS 

$CLASS_PATH has class path
$CLASS has the name of main class
EXEC="/usr/bin/jsvc"

I can start and stop the service using following commands

service myscriptfilename start
service myscriptfilename stop

Now I added a new argument to my program called "myflag" . It works fine on windows box . Now I am having difficulty passing the new argument to my program on my linux box using the shell script.

Now I am starting my service as

service myscriptfilename start myflag

I can get the value of myflag using $2 in shell script. I am trying to figure out how do I pass that to my program

How can i pass my "myflag" to my program from shell script in the following line?

$EXEC -home "$JAVA_HOME" -cp "$CLASS_PATH" -outfile "$LOG_OUT" -errfile "$LOG_ERR" -pidfile "$PID" $1 $CLASS

I can get the value of myflag using $2 in shell scriipt . I am trying to figure out how do I pass that to my program? — Kenner Dev
– Kenner Dev, Commented Nov 22, 2015 at 0:58
Who knows how your program parses command line arguments. There's no agreed standard, so there could be a million ways. It's your program after all, and you should know better than us... (You didn't even say what's $EXEC, for that matter; maybe it's known to all Java programmers? I'm not sure.) — 4ae1e1
– 4ae1e1, Commented Nov 22, 2015 at 1:04
I am looking for args[0].It is working fine in windows box . I am not sure where to pass that argument in linux — Kenner Dev
– Kenner Dev, Commented Nov 22, 2015 at 1:05

user3707125 · Accepted Answer · 2015-11-22 01:17:42Z

1

I am considering that $EXEC is java executable, $1 is your JAR, $CLASS is your main class. In this case just append ${@:2} to the end of the line:

$EXEC -home "$JAVA_HOME" -cp "$CLASS_PATH" -outfile "$LOG_OUT" -errfile "$LOG_ERR" -pidfile "$PID" $1 $CLASS ${@:2}

answered Nov 22, 2015 at 1:17

user3707125

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6 Comments

Kenner Dev Over a year ago

EXEC="/usr/bin/jsvc" and $1=start from the command service myscriptfilename start myflag

user3707125 Over a year ago

Should work nevertheless - it has similar execution options.

user3707125 Over a year ago

@KennerDev, can you investigate which part doesn't work? Have you tried replacing ${@:2} with myflag? There are two places where your parameter may not be passed: service start and jsvc .... Try to determine which of these doesn't work.

Kenner Dev Over a year ago

It is at jsvc level .It is passing at service start.

user3707125 Over a year ago

@KennerDev, are you retrieving them through DaemonContext ?

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