Javascript "Uncaught SyntaxError: Unexpected token ;" error

Question

When i run this code it gives a syntax error in Chrome.

var leanboo = confirm("RFT(ready for testing)?") // Co1,Cr1
console.log(leanboo)
var text = prompt("What are your thoughts of this Area?")
console.log(text)

function crashCourseTesterIdGenerator(min, max) {
console.log(Math.floor((Math.random() * max) + min);)
} //Co1,Cr2
var testermin = prompt("Id generating min:")
var testermax = prompt("Id generating max:")
console.log(crashCourseTesterIdGenerator(testermin, testermax))

Does it have to do with the method name length or am i just forgetting some semicolons?

This question appears to be off-topic because it is about a simple typographic error. — Pointy
– Pointy, Commented Nov 18, 2013 at 19:12
@Pointy, but you still answered it anyway? Kind of defeats the purpose of dissuading newcomers to post this type of question if you're just going to answer it anyway. — maček
– maček, Commented Nov 18, 2013 at 19:13
@maček well the point of closing "typo questions" is that they don't do anybody any good as a long-term reference question, but this person still had a problem to be solved. I suppose I could have just typed a comment. I didn't put a lot of deep thought into the situation :) — Pointy
– Pointy, Commented Nov 18, 2013 at 19:14
Aside from the obvious syntax error, presumably you have put the console.log there to see why it's not working - if it isn't obvious the function has no return statement. — Emissary
– Emissary, Commented Nov 18, 2013 at 19:15
jslint.com or jshint.com or use your debugger which will point you to the line. — epascarello
– epascarello, Commented Nov 18, 2013 at 19:15

Pointy · Accepted Answer · 2013-11-18 19:12:35Z

6

You've got a ; inside the console.log() call in that function.

answered Nov 18, 2013 at 19:12

Pointy

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1 Comment

ooransoy Over a year ago

Thanks! (Can't upvote your answer because of the 15 reputation limit...)

darcher · Accepted Answer · 2013-11-18 19:16:26Z

1

var leanboo = confirm("RFT(ready for testing)?"); // Co1,Cr1
console.log(leanboo);
var text = prompt("What are your thoughts of this Area?");
console.log(text);

function crashCourseTesterIdGenerator(min, max) {
console.log(Math.floor((Math.random() * max) + min));
} //Co1,Cr2
var testermin = prompt("Id generating min:");
var testermax = prompt("Id generating max:");
console.log(crashCourseTesterIdGenerator(testermin, testermax));

Should fix ya right up.

answered Nov 18, 2013 at 19:16

darcher

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Comments

Ian · Accepted Answer · 2013-11-19 12:56:10Z

0

Semi colons go at the end of each statement in Javascript. You're missing them.

They're not strictly required, but you can commit all kinds of hard-to-find errors without them where Javascript doesn't know when one statement ends and another begins. Best to make it a matter of personal law to always use them and you're future self will save lots of debugging time.

And then you have an extra one:

console.log(Math.floor((Math.random() * max) + min);)

before the end of the line. Which is actually causing the error message.

edited Nov 19, 2013 at 12:56

answered Nov 18, 2013 at 19:13

Ian

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2 Comments

ooransoy Over a year ago

So where i searched 'js randomizing between numbers' didn't know that... But thanks for the tip! :)

Ian Over a year ago

@avaragecoder There is a depressing amount of really badly programmed example Javascript code around. Be careful of copying stuff from random sites. Because Javascript is often used by non-programmers, who hack and share code around, the quality is often terrible. If you can, get hold of Douglas Crockford's book on Javascript, he shows how it should be used in a safe and professional manner, that will give you a good foundation, at least.

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