split a string having multiple conditions using regex

Question

I m having a string as below

  This is a test\nAnother test\n#art\n#paintings#collections

From which i have pick the words - art, paintings,collections.

I have written a java program for that here. The code -

  String str = "This is a test\nAnother test\n#art\n#paintings#collections";


    String tag_name ="";
    String[] sp = str.split(" |\n");
    for (int j =0; j<sp.length; j++) {
        //System.out.println(""+sp[j]);
        if ( String.valueOf(sp[j].charAt(0)).equals("#")) {                
            tag_name = sp[j];
            String[] np = tag_name.split("#");
            for (int k = 0; k<np.length; k++) {
                if(np[k].length() >0 ) {
                    tag_name = np[k].replaceAll("\n", "");
                    System.out.println(""+ np[k]);
                }
            }                
            //System.out.println("" + tag_name);
        }
    }

Please suggest how can i do this using a more strong regex code.

It's not clear what you're asking here. What is wrong with the above code? — Oliver Charlesworth
– Oliver Charlesworth, Commented Feb 23, 2014 at 17:08
it is having split two times and two for loops. i thought if it can be reduced. — Pradyut Bhattacharya
– Pradyut Bhattacharya, Commented Feb 23, 2014 at 17:10

aliteralmind · Accepted Answer · 2014-02-23 17:16:30Z

1

If I'm understanding your requirements, you want to find all words following #. If so, this works:

   import  java.util.regex.Matcher;
   import  java.util.regex.Pattern;
/**
   <P>{@code java ArtTypesXmpl}</P>
 **/
public class ArtTypesXmpl  {
   public static final void main(String[] igno_red)  {
     String sToSearch = "This is a test\nAnother test\n#art\n#paintings#collections";

     Matcher mHashThenWord = Pattern.compile("#(\\w+)").matcher(sToSearch);

     while(mHashThenWord.find())  {
        System.out.println(mHashThenWord.group(1));
     }
   }
}

Output:

[C:\java_code\]java ArtTypesXmpl
art
paintings
collections

JavaDoc on Pattern and Matcher: http://docs.oracle.com/javase/7/docs/api/java/util/regex/package-summary.html

answered Feb 23, 2014 at 17:16

aliteralmind

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1 Comment

Pradyut Bhattacharya Over a year ago

this is really cool. Never quite seen all this magnificence anywhere :)

Rakesh KR · Accepted Answer · 2014-02-23 17:18:42Z

0

Try with

String[] sp = str.split("\\s|\\n");

From Here

Twelve characters have special meanings in regular expressions: the backslash \, the caret ^, the dollar sign $, the period or dot ., the vertical bar or pipe symbol |, the question mark ?, the asterisk or star *, the plus sign +, the opening parenthesis (, the closing parenthesis ), the opening square bracket [, and the opening curly brace {. These special characters are often called metacharacters.

edited Feb 23, 2014 at 17:18

answered Feb 23, 2014 at 17:08

Rakesh KR

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1 Comment

Boann Over a year ago

Escaping those characters isn't necessary, but at least credit the place you're lifting that text from.

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