I'm trying to split a String using regex with Java.
The string looks like this: {'tata','toto','titi'}
But {} describes the order of the preceding liberal, so it doesn't work for me.
What regex should I use to get this result :
tata
toto
titi
-
2Can you post what code you have so far?Drew Kennedy– Drew Kennedy2014-11-18 18:30:39 +00:00Commented Nov 18, 2014 at 18:30
-
\d{X} means in regex that it occurs X times. how to ignore the bracesuser4266839– user42668392014-11-18 18:32:59 +00:00Commented Nov 18, 2014 at 18:32
-
3Are you trying to parse an existing data-interchange format? If so there may be a better solution than regex.FriendlyAgent– FriendlyAgent2014-11-18 18:34:27 +00:00Commented Nov 18, 2014 at 18:34
Add a comment
|
3 Answers
You can use this regex:
String str = "{'tata','toto','titi'}";
String[] arr = str.split("[{},']+");
//=> tata, toto, titi
There is no need to escape { or } inside character class.
Comments
You can use \ to disable the special meaning of any character in a regex.
Since \ itself has a special meaning in a String you will need to duplicate it if you specify your regex directly in a String literal in java. So replace "{something}" with \\{something\\}".
Comments
String a = "{'tata','toto','titi'}"
a = a.replace("{'", ""); // get rid of opening bracket and singlequote
a = a.replace("'}", ""); // get rid of ending bracket and singlequote
String[] b = a.split("','"); // split on commas surrounded by singlequotes
This should give you an array of just the words you want. I guess it's not specifically regex, but it should do the right thing anyway.
1 Comment
DaaaahWhoosh
Totally forgot about replace not changing the original string. Thanks for setting me straight, whoever you were.