how to convert string object into time object in python 2.4

Question

I have two string objects:

dt1[1]="00:58:00"    
dt2[1]="01:02:00"

If I do,

FMT='%H:%M:%S'
SD=datetime.datetime(*time.strptime(dt1[1], FMT)[:6])
FD=datetime.datetime(*time.strptime(dt2[1], FMT)[:6])

it translates to 1900-01-01 00:58:00 and 1900-01-01 01:02:00 but I want only the time part not the date.

I have converted date into string and subtracted only the time part from it. Now i need to convert them to time object again and do dt2[1]-dt[1] to find the time difference.

How can I do it.

Martijn Pieters · Accepted Answer · 2014-04-04 06:35:20Z

2

To get datetime.time() objects, just call the datetime.datetime.time() method on the result:

>>> import datetime
>>> import time
>>> dt1 = '00:58:00'
>>> dt2 = '01:02:00'
>>> FMT='%H:%M:%S'
>>> datetime.datetime(*time.strptime(dt1, FMT)[:6])
datetime.datetime(1900, 1, 1, 0, 58)
>>> datetime.datetime(*time.strptime(dt1, FMT)[:6]).time()
datetime.time(0, 58)
>>> datetime.datetime(*time.strptime(dt2, FMT)[:6]).time()
datetime.time(1, 2)

However, if you are going to subtract these, use the datetime.datetime() objects! You cannot subtract datetime.time() objects:

>>> res1 = datetime.datetime(*time.strptime(dt1, FMT)[:6])
>>> res2 = datetime.datetime(*time.strptime(dt2, FMT)[:6])
>>> res2.time() - res1.time()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for -: 'datetime.time' and 'datetime.time'
>>> res2 - res1
datetime.timedelta(0, 240)

answered Apr 4, 2014 at 6:35

Martijn Pieters

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7 Comments

Debayan Over a year ago

I need to subtract only time part. If I subtract date object it will give me 1 day something the original objects are having dates like this : 03-APR-2014 00:58 02-APR-2014 01:02 so if i subtract it, it will show 23 hr something, but i only need to subtract hour and minute part like 01:02 - 00:58 and it will give me 4 mins.

Martijn Pieters Over a year ago

@Debayan: I know, but if you need to subtract the times, you need datetime objects. It doesn't matter for your usecase that the dates an those objects are useless; only that they are the same date.

Debayan Over a year ago

I can even convert them entirely to minutes and subtract it.

Martijn Pieters Over a year ago

@Debayan: sure, but that'd require a different method of parsing; the time and datetime modules don't deal in durations but in fixed points in time (date, or date + time or time of day) instead.

Debayan Over a year ago

So any idea how to find the time difference

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