I have researched how to do this, but when I print the date and time separately there are other values that appear e.g. 00:00:00 and 1900-01-01.
Code:
import datetime
date = datetime.datetime.strptime('17/12/2018', '%d/%m/%Y')
time = datetime.datetime.strptime('13:26:09', '%H:%M:%S')
print(date)
print(time)
Expected Output:
17/12/2018
13:26:09
>>>
Output:
2018-12-17 00:00:00
1900-01-01 13:26:09
>>>
You can simply use the datetime.date() and datetime.time() functions:
import datetime
date = datetime.datetime.strptime('17/12/2018', '%d/%m/%Y') # this is a datetime
time = datetime.datetime.strptime('13:26:09', '%H:%M:%S') # this is also a datetime
print(date.date()) # just the date
print(time.time()) # just the time
Output:
2018-12-17 # do date.strftime('%%d/%m/%Y') to create the string representation you want
13:26:09 # default visualisation is same as you want
You create 2 datetime instances - one only by specifying the time, the other buy only specifying the date. The other param is supplied by default.
Alternativly you can use:
date = datetime.datetime.strptime('17/12/2018', '%d/%m/%Y').date() # date object
time = datetime.datetime.strptime('13:26:09', '%H:%M:%S').time() # time object
date part from the via datetime.datetime.strptime(...) created date() - it will be displayers with it's default representation - which for me is 2018-12-17 - if you want your special format 17/12/2018 you need to strftime the date() object