java.lang.NumberFormatException for input string ""

Question

I am trying to take a string and convert it into a long how ever I keep getting the error mentioned above

public long[] stringToLongDecrypt()
{
    long ciphertext[] = new long[elements.length];
    for(int i=0; i<ciphertext.length; i++)
    {
        ciphertext[i] = Long.parseLong(elements[i].trim(), 16);
    }
    return ciphertext;
}

Any ideas?

That's the correct behavior. What are you expecting from empty string. — Braj
– Braj, Commented Apr 23, 2014 at 4:25

Abimaran Kugathasan · Accepted Answer · 2014-04-23 04:25:32Z

1

You have to parse, only a valid numbers, empty String "" is not a valid number. So, you have to check it before parsing it. Otherwise, you will get NumberFormatException.

public long[] stringToLongDecrypt() {
    long ciphertext[] = new long[elements.length];
    for(int i=0; i<ciphertext.length; i++) {
       if(elements[i] != null && !elements[i].trim().isEmpty()) {
          ciphertext[i] = Long.parseLong(elements[i].trim(), 16);
       }
    }
    return ciphertext;
}

answered Apr 23, 2014 at 4:25

Abimaran Kugathasan

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Comments

Olesya Razuvayevskaya · Accepted Answer · 2014-04-23 04:28:16Z

0

Long cannot parse input which is of String datatype. Try using the following instead:

 Long.valueOf(elements[i].trim()).longValue();

answered Apr 23, 2014 at 4:28

Olesya Razuvayevskaya

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2 Comments

Bhesh Gurung Over a year ago

No matter what you do, parse or valueOf, you cannot convert an empty string into a number.

Braj Over a year ago

@Lesya Have you tested it before posting?

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