java.lang.NumberFormatException: For input string

Question

the eclipse tells that lang and i cant find a solution

Exception in thread "main" java.lang.NumberFormatException: For input string: "2463025552" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at Main.main(Main.java:31)

String s2[]=s.split("\\,");
Records rec=new Records();
rec.setName(s1[0]);
rec.setAddres(s2[0]);

phone  = Integer.parseInt( s2[1].trim() );
System.out.println(phone);

I read from file in this format name-adres,phone and ad in arraylist put for phone i have problem

BenMorel · Accepted Answer · 2014-06-16 12:00:07Z

29

Integer.parseInt throws a NumberFormatException if the passed string is not a valid representation of an integer. here you are trying to pass 2463025552 which is out of integer range.

use long instead

long phone = Long.parseLong(s2[1].trim() )

edited Jun 16, 2014 at 12:00

BenMorel

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answered Dec 18, 2012 at 14:35

PermGenError

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Comments

Thorn G · Accepted Answer · 2012-12-18 14:37:38Z

16

The real problem is that a phone number is not an integer. It is a String. You should not store it as a number, for reasons similar to the problem you are encountering now. The same applies for ZIP codes, sports team's jersey numbers, and a host of other "fake" numbers.

answered Dec 18, 2012 at 14:37

Thorn G

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4 Comments

Alex Stybaev Over a year ago

+1 to Tom G, using Long or other numeric type can cause issues in future.

jn1kk Over a year ago

This is the correct response. What if the phone number is 000-0001. Do you really want to store it as 1? What would you show the user?

PermGenError Over a year ago

+1 tom, agreed ... way better to make it an string than long .. sad i dint get that tought while answering :P,

Βίκτορας ανδρεάδης Over a year ago

I tern the int varible to String ?

Harsh Kothari · Accepted Answer · 2012-12-18 14:38:30Z

4

A Signed 32 Bit Integer can only read upto 2^31. You have to use a bigger datatype. long will get you up to 2^63.

answered Dec 18, 2012 at 14:38

Harsh Kothari

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Comments

ramesh · Accepted Answer · 2012-12-18 15:27:11Z

2

The basic thing is that, we don't need a phone number to be part of a arithmetic calculation like addition, subtraction etc. Hence we can take it as a String safely.

answered Dec 18, 2012 at 15:27

ramesh

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Comments

Pradeep Simha · Accepted Answer · 2012-12-18 14:36:09Z

1

2463025552

is a out of range for int data type, try giving lesser number. Also check if it is in correct number format (like no spaces etc)

answered Dec 18, 2012 at 14:36

Pradeep Simha

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1 Comment

Paŭlo Ebermann Over a year ago

It is a given phone number, we can't really change it so it fits into an int.

Kanagaraj M · Accepted Answer · 2012-12-18 14:44:04Z

0

Change your data type to long or bigint. Your string is too long then int thats why it have exception..

answered Dec 18, 2012 at 14:44

Kanagaraj M

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Comments

Ravi · Accepted Answer · 2012-12-18 14:45:47Z

0

Integer.parseInt( s2[1].trim() ); here is your problem. So, change your parsing Integer to Long

edited Dec 18, 2012 at 14:45

answered Dec 18, 2012 at 14:38

Ravi

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1 Comment

Βίκτορας ανδρεάδης Over a year ago

I change from Integer to long and works perfect.. A lot of thanks for help.

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