Numpy Index Iterator

Question

I don't remember whether this is Python or numpy specific. I once found an index iterator that is not in the main introduction and however I try to look for it, I couldn't find it anymore. This is what it gave me:

>>> foo = ones((1,2,3))

>>> for i in foo.getThisMagicIteratorIndexThiny():
>>>     print i
(0,0,0)
(0,0,1)
(0,0,2)
(0,1,0)

And, foo[i] would return the corresponding value. Does anyone know which iterator I am talking about?

You can use for idx in np.ndindex(foo.shape):

gg349
– gg349

2014-05-15 09:11:17 +00:00
Commented May 15, 2014 at 9:11 — gg349
– gg349, Commented May 15, 2014 at 9:11
Perfect. If you add an answer, we can close this.

FooBar
– FooBar

2014-05-15 10:46:55 +00:00
Commented May 15, 2014 at 10:46 — FooBar
– FooBar, Commented May 15, 2014 at 10:46

ρss · Accepted Answer · 2014-05-15 10:59:15Z

1

As per flebool's comment the solution is to use for idx in np.ndindex(foo.shape):

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