Python Numpy Array indexing

Question

I am having a small difficulty with Numpy indexing. The script gives only the index of the last array three times when it supposed to give index of three different arrays (F_fit in the script). I am sure it is a simple thing, but I haven't figured it out yet. The 3_phases.txt file contains these 3 lines

1  -1   -1  -1   1   1
1   1    1  -1   1   1
1   1   -1  -1  -1   1

Here is the code:

import numpy as np
import matplotlib.pyplot as plt

D = 12.96
n = np.arange(1,7)

F0 = 1.0
x = np.linspace(0.001,4,2000)
Q = 2*np.pi*np.array([1/D, 2/D, 3/D, 4/D, 5/D, 6/D])
I = (11.159, 43.857, 26.302, 2.047, 0.513, 0.998)    
phase = np.genfromtxt('3_phases.txt')

for row in phase:

    F = (np.sqrt(np.square(n)*I/sum(I)))*row
    d = sum(i*(np.sin(x*D/2+np.pi*j)/(x*D/2+np.pi*j))for i,j in zip(F,n))
    e = sum(i*(np.sin(x*D/2-np.pi*j)/(x*D/2-np.pi*j))for i,j in zip(F,n))
    f_0 = F0*(np.sin(x*D/2)/(x*D/2))
    F_cont = np.array(d) + np.array(e) + np.array(f_0)
    plt.plot(x,F_cont,'r')
    #plt.show()
    plt.clf()

D2 = 12.3
I2 = (9.4, 38.6, 8.4, 3.25, 0, 0.37)
Q2 = 2*np.pi*np.array([1/D2, 2/D2, 3/D2, 4/D2, 5/D2, 6/D2])
n2 = np.arange(1,7)

for row in phase:
    F2 = (np.sqrt(np.square(n2)*I2/sum(I2)))*row
    plt.plot(Q2,F2,'o')
    #plt.show()
    F_data = F2
    Q_data = Q2
    I_data = np.around(2000*Q2/(4-0.001))
    I_data = np.array(map(int,I_data))
    F_fit = F_cont[I_data]
    print F_fit
    R2 = (1-(sum(np.square(F_data-F_fit))/sum(np.square(F_data-np.mean(F_data)))))

Any help would be appreciated.

askewchan · Accepted Answer · 2013-04-26 21:10:06Z

You are redefining F_cont each time you go through your first loop. By the time you get to your second loop (with all the _2 values) you only have access to the F_cont from the last row.

To fix this, move your _2 definitions above your first loop and only do the loop once, then you'll have access to each F_cont and your printouts will be different.

The following code is identical to yours except for the rearrangement described above, as well as the fact that I implemented my comment from above (using n/D in your Q's).

import numpy as np
import matplotlib.pyplot as plt

D = 12.96
n = np.arange(1,7)

F0 = 1.0
x = np.linspace(0.001,4,2000)
Q = 2*np.pi*n/D
I = (11.159, 43.857, 26.302, 2.047, 0.513, 0.998)    
phase = np.genfromtxt('3_phases.txt')

D2 = 12.3
I2 = (9.4, 38.6, 8.4, 3.25, 0, 0.37)
Q2 = 2*np.pi*n/D2
n2 = np.arange(1,7)

for row in phase:

    F = (np.sqrt(np.square(n)*I/sum(I)))*row
    d = sum(i*(np.sin(x*D/2+np.pi*j)/(x*D/2+np.pi*j))for i,j in zip(F,n))
    e = sum(i*(np.sin(x*D/2-np.pi*j)/(x*D/2-np.pi*j))for i,j in zip(F,n))
    f_0 = F0*(np.sin(x*D/2)/(x*D/2))
    F_cont = np.array(d) + np.array(e) + np.array(f_0)
    plt.plot(x,F_cont,'r')
    plt.clf()

    F2 = (np.sqrt(np.square(n2)*I2/sum(I2)))*row
    plt.plot(Q2,F2,'o')
    F_data = F2
    Q_data = Q2
    I_data = np.around(2000*Q2/(4-0.001))
    I_data = np.array(map(int,I_data))
    F_fit = F_cont[I_data]
    print F_fit
    R2 = (1-(sum(np.square(F_data-F_fit))/sum(np.square(F_data-np.mean(F_data)))))

lvc · Accepted Answer · 2013-04-26 10:12:47Z

0

F_fit is being calculating from I_data, which is in turn being calculated from Q2. Q2 is set outside the loop, and doesn't depend on row - perhaps you meant I_data to be a function of F2 instead?

answered Apr 26, 2013 at 10:12

lvc

35.2k10 gold badges76 silver badges100 bronze badges

2 Comments

user2095624 Over a year ago

well, F_cont has three arrays and I want to pick the values from each array giving the same indices of I_data for each array. But I am having only three times the values for the last arrays instead of all three arrays of F_cont

askewchan Over a year ago

@user2095624, No it doesn't, it's a 1d array and F_cont.shape is (2000,)

Collectives™ on Stack Overflow

Python Numpy Array indexing

2 Answers 2

Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related