Django get urlpatterns regex by view name

Question

I am not looking for from django.core.urlresolvers import reverse
what I want to do is : I have a urlpattern:

urlpatterns = patterns('xxx.views',
    url(r'^search/$', 'resume_search', name='xxx_resume_search'),
    url(r'^recruit/manage/(?P<id>[0-9]+)$', 'recruit_manage', name='xxx_recruit_manage'),
)

I want to do something like

rr = reverse_regex('xxx_recruit_manage')

rr would be '^recruit/manage/(?P<id>[0-9]+)$'

if

urlpatterns = patterns('xxx.views',
    url(r'^search/$', 'resume_search', name='xxx_resume_search'),
    url(r'^recruit/manage/$', 'recruit_manage', name='xxx_recruit_manage'),
)
    url(r'^recruit/manage/(?P<id>[0-9]+)$', 'recruit_manage', name='xxx_recruit_manage'),
)

rr would be ['^recruit/manage/$','^recruit/manage/(?P<id>[0-9]+)$']

How can I make it?

Henrik Andersson · Accepted Answer · 2014-08-07 08:38:11Z

1

The urls.py is like any other module where you can import it and see what things it has.

The below is quite crude but works and shows off the API.

import myapp.urls as my_urls

regex_pattern = my_urls.urlpatterns[2].regex.pattern
>> ^recruit/manage/(?P<id>[0-9]+)

a bit better

regex_object = filter(lambda x:'xxx_recruit_manage' == x.name, my_urls.urlpatterns)
>> [<RegexURLPattern recruit_manage ^recruit/manage/(?P<id>[0-9]+)$>]

edited Aug 7, 2014 at 8:38

answered Aug 7, 2014 at 8:26

Henrik Andersson

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2 Comments

Mithril Over a year ago

Wonderful!Thank you.'xxx_recruit_manage' == x.name is better, in may result to match a url name contain 'xxx_recruit_manage', such as 'xxx_recruit_manage_list'.

Henrik Andersson Over a year ago

Yes, of course, updated the answer to reflect that :) Just remember that you have two name with the same name.

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