Javascript regex ends with pattern

Question

I'm trying to write a regex in javascript to identify string representations of arbitrary javascript functions found in json, ie. something like

{
  "key": "function() { return 'I am a function'; }"
}

It's easy enough to identify the start, but I can't figure out how to identify the ending double quotes since the function might also contain escaped double quotes. My best try so far is

/"\s*function\(.*\)[^"]*/g

which works nicely if there are no double quotes in the function string. The end of a json key value will end with a double quote and a subsequent comma or closing bracket. Is there some way to retrieve all characters (including newline?) until a negated pattern such as

not "/s*, and not "/s*}

... or do I need to take a completely different approach without regex?

Here's is the current test data I'm working with: http://regexr.com/39pvi

Avinash Raj · Accepted Answer · 2014-10-26 17:52:33Z

1

Seems like you want something like this,

"\s*function\(.*\)(?:\\.|[^\\"])*

It matches also the inbetween \" escaped double quotes.

DEMO

edited Oct 26, 2014 at 17:52

answered Oct 26, 2014 at 17:33

Avinash Raj

175k32 gold badges247 silver badges289 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

friedi Over a year ago

it's not working if there is \n in the body of the function like this: "function() { return 'hello \n fun ction stuff'; }"

Avinash Raj Over a year ago

it works, see regex101.com/r/oY5jU1/1 . [^"\\]* would match newline characters also.

Avinash Raj Over a year ago

if there is any \n present in this () block then he need to change the regex like "\s*function\([\S\s]*?\)(?:[^"\\]|\\")*

friedi Over a year ago

You can switch the two parts and leave out the \\: "\s*function\(.*\)(?:\\"|[^"])*". See regex101.com/r/oY5jU1/3

Collectives™ on Stack Overflow

Javascript regex ends with pattern

1 Answer 1

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related