Regex for end of string

Question

I can't find the magic formula to get my regex working in Javascript. let's say I have:

const branchnames = [
    { name:'WICO-29', key:1 },
    { name:'WICO-9', key:2 },
    { name:'wico-2', key:3 },
    { name:'wiCo-2: description', key:4 },
    { name:'WiCO-2 example ', key:5 },
    { name:'WiCO-2-dosomething', key:6 },
    { name:'wiCO-2, great', key:7 },
];

I would like to recover every names excepts for the first two. Hence I am looking for a regex looking for "wico-2" (not case sensitive), followed either by nothing or a non alphanumerical character. Following attempts didn't work...

const reg = new RegExp(/wico-2[ ,:-]?$/, "i"); // miss: 4,5,6,7
const reg = new RegExp(/wico-2\W/, "i"); // miss: 3
const reg = new RegExp(/wico-2\W?/, "i"); // wrong:1
const reg = new RegExp(/wico-2\W?$/, "i"); // only 3

branchnames.forEach( element => {
    console.log ( element.name.match(reg));
});

any help ? thanks !

@RokoC.Buljan Because I would like to recover every names excepts for the first two. — Mohammad
– Mohammad, Commented Oct 13, 2016 at 14:04

Thomas Ayoub · Accepted Answer · 2016-10-13 14:02:31Z

1

I would use /wico-2(?:\D+|$)/ to do this:

const branchnames = [
    { name:'WICO-29', key:1 },
    { name:'WICO-9', key:2 },
    { name:'wico-2', key:3 },
    { name:'wiCo-2: description', key:4 },
    { name:'WiCO-2 example ', key:5 },
    { name:'WiCO-2-dosomething', key:6 },
    { name:'wiCO-2, great', key:7 },
];

const reg = new RegExp(/wico-2(?:\D+|$)/, "i"); 

branchnames.forEach( element => {
    console.log ( element.name.match(reg));
});

Explanation of (?:\D+|$):

Non-capturing group (?:\D+|$)
- 1st Alternative \D+ : matches any character that's not a digit (equal to [^0-9])
- + Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
- 2nd Alternative $: asserts position at the end of the string

edited Oct 13, 2016 at 14:02

answered Oct 13, 2016 at 13:58

Thomas Ayoub

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5 Comments

Teepeemm Over a year ago

@bertrand By the way, the ?: only makes the parentheses not count as matching groups. You could leave that out to make the regular expression easier to read, possibly at the expense of speed.

Bertrand Engogram Over a year ago

Thank you. Actually, in this case speed is clearly not an issue, and I am in favor of something easy to read / understand ... actually before the answers from the community, I was doing :

Bertrand Engogram Over a year ago

const regexp1 = currentTaskKey + '\\W'; const reg1 = new RegExp(regexp1, 'i'); const regexp2 = currentTaskKey + '$'; // task key not followed by anything const reg2 = new RegExp(regexp2, 'i'); return element.name.match(reg1) || element.name.match(reg2);

Bertrand Engogram Over a year ago

const regexp1 = currentTaskKey + '\\W'; const reg1 = new RegExp(regexp1, 'i'); const regexp2 = currentTaskKey + '$'; const reg2 = new RegExp(regexp2, 'i'); return element.name.match(reg1) || element.name.match(reg2);

Bertrand Engogram Over a year ago

(sorry for the mess... comments cannot be formatted...)

Shekhar Khairnar · Accepted Answer · 2016-10-13 14:18:41Z

1

You can use regex as /wico-2(?!\d)/gi

const branchnames = [
    { name:'WICO-29', key:1 },
    { name:'WICO-9', key:2 },
    { name:'wico-2', key:3 },
    { name:'wiCo-2: description', key:4 },
    { name:'WiCO-2 example ', key:5 },
    { name:'WiCO-2-dosomething', key:6 },
    { name:'wiCO-2, great', key:7 },
];
const reg = new RegExp(/wico-2(?!\d)/, "gi");

branchnames.forEach( element => {
  if(element.name.match(reg)){
     console.log (element);
  }
});

edited Oct 13, 2016 at 14:18

answered Oct 13, 2016 at 14:16

Shekhar Khairnar

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1 Comment

Roko C. Buljan Over a year ago

Your example will select also fico-3: wico-26

Redu · Accepted Answer · 2016-10-13 14:09:23Z

0

One might do as follows;

var branchnames = [
    { name:'WICO-29', key:1 },
    { name:'WICO-9', key:2 },
    { name:'wico-2hello', key:3 },
    { name:'wico-2', key:3 },
    { name:'wiCo-2: description', key:4 },
    { name:'WiCO-2 example ', key:5 },
    { name:'WiCO-2-dosomething', key:6 },
    { name:'wiCO-2, great', key:7 },
];
branchnames.forEach(bn => /wico-2(?=[^\dA-Za-z]|$)/i.test(bn.name) && console.log(bn.name));

edited Oct 13, 2016 at 14:09

answered Oct 13, 2016 at 14:02

Redu

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1 Comment

Thomas Ayoub Over a year ago

like WiCO-2-dosomething? @RokoC.Buljan

brso05 · Accepted Answer · 2016-10-13 14:19:00Z

0

You could do this:

/wico-2(([ ,:-]+|$).*$)/

Here is a link to regex tester:Regex

edited Oct 13, 2016 at 14:19

answered Oct 13, 2016 at 14:03

brso05

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1 Comment

Roko C. Buljan Over a year ago

"Don't" use spaces in regex

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