How to sort Integer Array in ksh | Unix Shell Scripting

Question

How to sort integer array in KornShell. Found this link, KornShell Sort Array of Integers but it seems to be not working and throwing error.

Code:

NUM_ARR[1]=-1
NUM_ARR[2]=-2
NUM_ARR[3]=-3
NUM_ARR[4]=-4
NUM_ARR[5]=-5
NUM_ARR[6]=-6
NUM_ARR[7]=-7
for file in /home/fimsctl/datafiles/outbound/timelog/timelog_file_*.csv ; do

    SORTED_NUM_ARR=`($(printf "%s\n" ${NUM_ARR[@]} | sort -n))`
 echo ${SORTED_NUM_ARR[*]}
 done

Output:

testb.ksh[118]: -7:  not found

anubhava · Accepted Answer · 2015-01-12 13:26:47Z

1

You can use sort with process substitution:

sort -n <(printf "%s\n" "${NUM_ARR[@]}")

answered Jan 12, 2015 at 13:26

anubhava

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4 Comments

Sachin Over a year ago

Where you've been till now!.. It's like you saved my life. Though it could had been simplest of the questions... Thanks a million!... I still don't get why $(printf "%s\n" ${NUM_ARR[@]} | sort -n) is not working.

anubhava Over a year ago

You're most welcome. printf "%s\n" "${NUM_ARR[@]}" | sort -n should also work.

emfi Over a year ago

how to assign that properly to a array variable?

emfi Over a year ago

set -A orderedArray $(printf "%s\n" "${arrayToOrder[@]}" | sort -n | tr "\n" " ");

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