Java Regex to replace specific character within parenthesis

Question

Need help in getting the java regex to replace = sing between parenthesis with #, my input text is

8=FIX.4.&49=(550=0449)&35=RIO&76=(AB=4560)&

expected output string

8=FIX.4.&49=(550#0449)&35=RIO&76=(AB#4560)&

So would like to replace = char only within (550=0449) and (AB=4560) with # so the output should contain (550#0449) and (AB#4560).

is it possible to have orphaned or nested "(" and ")" or will they always have an open and close perenthesis? — PeonProgrammer
– PeonProgrammer, Commented Feb 5, 2015 at 22:40
It can be nested but it will be balanced, every opening ( will have closing ) so every = char within ( needs to be replaced even from nested. — Pramod
– Pramod, Commented Feb 5, 2015 at 22:46

Bohemian · Accepted Answer · 2015-02-05 23:14:39Z

3

I like anubhava's answer, but if you want to be more strict and assert there are non-blank terms and opening and closing brackets, capture the terms and write them back using back references:

str = str.replaceAll("(\\(\\w+)=(\\w+\\))", "$1#$2");

answered Feb 5, 2015 at 23:14

Bohemian♦

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hwnd · Accepted Answer · 2015-02-05 22:58:34Z

1

You can use:

String repl = str.replaceAll("=(?=[^()]*\\))", "#");

(?=[^()]*\)) is a lookahead that will make sure to match = only when there is a ) following it.

edited Feb 5, 2015 at 22:58

hwnd

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answered Feb 5, 2015 at 22:40

anubhava

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