How can i do this in java :
given a string, for each text in parenthesis, if it contains "blabla" then remove all text in these parenthesis including parenthesis themselves
example :
some string (some text) (blabla foo bar) => some string (some text)
some string (some text) (blabla) => some string (some text)
some string (ex ex) => unchanged (because words in parenthesis doesn't contain "blabla")
thanks.
You could try the below replaceAll function.
string.replaceAll("\\([^()]*blabla[^()]*\\)", "");
Explanation:
\\( Matches a literal ( symbol.[^()]* Negated character class which matches any character but not of ( or ) zero or more times.blabla Matches the string blabla[^()]* Negated character class which matches any character but not of ( or ) zero or more times.\\) Matches a literal ) symbol.
\\(.*?\\bblabla\\b.*?\\)
Try this.Replace by empty string.
http://regex101.com/r/zU7dA5/12
Use \b to make sure you replace only blabla and not abcblablaas
String x = "some string (some text) (blabla)";
String replace = x.replace("(blabla)", "");
System.out.println(""+replace);
