I have an array that looks like this:
var arr: [Int] = [1,2,3,4,5]
In order to print this, I would like to convert this to:
var newArr: [String?] = ["1","2","3","4","5"]
How can I solve this problem?
6 Answers
Airspeed Velocity gave you the answer:
var arr: [Int] = [1,2,3,4,5]
var stringArray = arr.map { String($0) }
Or if you want your stringArray to be of type [String?]
var stringArray = arr.map { Optional(String($0)) }
This form of the map statement is a method on the Array type. It performs the closure you provide on every element in the array, and assembles the results of all those calls into a new array. It maps one array into a result array. The closure you pass in should return an object of the type of the objects in your output array.
We could write it in longer form:
var stringArray = arr.map {
(number: Int) -> String in
return String(number)
}
EDIT:
If you just need to install your int values into custom table view cells, you probably should leave the array as ints and just install the values into your cells in your cellForRowAtIndexPath method.
func tableView(tableView: UITableView,
cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("cell",
forIndexPath: indexPath) as! MyCustomCellType
cell.textLabel?.text = "\(arr[indexPath.row])"
return cell
}
Edit #2:
If all you want to to is print the array, you'd be better off leaving it as an array of Int objects, and simply printing them:
arr.forEach { print($0) }
Comments
Update: Swift 5
You can do it using following code:
var arr: [Int] = [1,2,3,4,5]
let stringArray = arr.map(String.init)
output:
["1", "2", "3", "4", "5"]
Comments
You should use
cell.textLabel?.text = "\(arr[indexPath.row])"
in order to present the value in the label as a String.
1 Comment
Javier Vieira
Qustion is not that, isn't it
Do it in place using the following piece of code:
Array(0...100).map { String($0) }
Comments
If you're looking do something like Python's .join(), Perl's join(), PHP's implode(), you can use .joined(separator: String) -- but only on a list of String values.
So you'll still need the .map as shown above to do the conversion, but once that's done, it looks a lot more like what you're used to:
let stringifiedNumberList = numberList
.map { String($0) }
.joined(separator: ", ")
If you want to get fancy...
One cool thing you can do is add "and" or "or" before the last element in the output, to provide an Oxford comma delimited list, by taking advantage of the .map already being there. The .enumerated() method can help out by giving you an index on each element the map iterates through:
let stringifiedNumberList = numberList
.enumerated()
.map {
if $0.0 == (numberList.count - 1) {
return "and " + String($0.1)
} else {
return String($0.1)
}
}
.joined(separator: ", ")
Comments
Declare your integer array like this :
let integerArray = [1 , 2 ,4 ,5]
Print your typecasted array Like this :
print(integerArray.map { String($0) })
And you can try typecasting to any data type like Float , Double , Int8 etc , here map will take each element from array and change to mentioned data type and assign it back to your array.
arr.map { String($0) }. If you really want the strings to be optional,arr.map { Optional(String($0)) }