[Xcode 7.1, iOS 9.1]
I have an array: var array: [String] = ["11", "43", "26", "11", "45", "40"]
I want to convert that (each index) into an Int so I can use it to countdown from a timer, respective of the index.
How can I convert a String array into an Int Array in Swift 2?
I've tried several links, none have worked and all of them have given me an error. Most of the code from the links is depreciated or hasn't been updated to swift 2, such as the toInt() method.
Use the map function
let array = ["11", "43", "26", "11", "45", "40"]
let intArray = array.map { Int($0)!} // [11, 43, 26, 11, 45, 40]
Within a class like UIViewController use
let array = ["11", "43", "26", "11", "45", "40"]
var intArray = Array<Int>!
override func viewDidLoad() {
super.viewDidLoad()
intArray = array.map { Int($0)!} // [11, 43, 26, 11, 45, 40]
}
If the array contains different types you can use flatMap (Swift 2) or compactMap (Swift 4.1+) to consider only the items which can be converted to Int
let array = ["11", "43", "26", "Foo", "11", "45", "40"]
let intArray = array.compactMap { Int($0) } // [11, 43, 26, 11, 45, 40]
instance member 'array' cannot be used on type TableViewControllerviewDidLoad(). Declare the variable on class level as implicit unwrapped optionalSwift 4, 5:
Use compactMap with cast to Int, solution without '!'.
'compactMap' filters nil values and applies a transformation.
let array = ["1","foo","0","bar","100"]
let arrayInt = array.compactMap { Int($0) }
print(arrayInt)
// [1, 0, 100]
Swift 4, 5:
The instant way if you want to convert string numbers into arrays of type int (in a particular case i've ever experienced):
let pinString = "123456"
let pin = pinString.map { Int(String($0))! }
And for your question is:
let pinArrayString = ["1","2","3","4","5","6"]
let pinArrayInt = pinArrayString.map { Int($0)! }
i suggest a little bit different approach
let stringarr = ["1","foo","0","bar","100"]
let res = stringarr.map{ Int($0) }.enumerate().flatMap { (i,j) -> (Int,String,Int)? in
guard let value = j else {
return nil
}
return (i, stringarr[i],value)
}
// now i have an access to (index in orig [String], String, Int) without any optionals and / or default values
print(res)
// [(0, "1", 1), (2, "0", 0), (4, "100", 100)]
A slightly different example
let digitNames = [0: "Zero", 1: "One", 2:"Two", 3: "Three",
4:"Four",5:"Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine", 10:"Ten"
]
let numbers = [16,58,510]
let strings = numbers.map { (number) -> String in
var number = number
var output = ""
repeat {
output = digitNames[number % 10]! + output
number /= 10
} while number > 0
return (output)
}
print(strings)
// strings is inferred to be of type [String]
// its value is ["OneSix", "FiveEight", "FiveOneZero"]
