.Batch file does not like variable for php executable

Question

I have a batch file which is going to be called by Windows Task Scheduler to execute given .php file.

However there seems to be a problem because when I provide full path to php.exe i.e.

start /B /wait C:\xampp\php\php.exe -f %inputTask% >> %outputDir%

batch file executes as it should, but when I try to give variable like so:

set php="C:\xampp\php"
start /B /wait C:\xampp\php\php.exe -f %inputTask% >> %outputDir%

if fails given the following error :

Windows cannot find '-f'. Make sure you type the name correctly, and then try again.

start /B /wait "C:\xampp\php\php.exe -f %inputTask%" >> %outputDir% — npocmaka
– npocmaka, Commented Jul 16, 2015 at 16:29

JosefZ · Accepted Answer · 2015-07-16 17:37:55Z

2

Start command considers the first double-quoted parameter to be a window title...

START: Start a program, command or batch script (opens in a new window.)

Syntax
  START "title" [/D path] [options] "command" [parameters]
Always include a TITLE this can be a simple string like "My Script" or just a pair of empty quotes "". According to the Microsoft documentation, the title is optional, but depending on the other options chosen you can have problems if it is omitted.

answered Jul 16, 2015 at 17:37

JosefZ

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1 Comment

Maciej Cygan Over a year ago

Yes that has solved the problem :) - adding empty quotes was sufficient

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