How to pass dynamic PHP variable as parameter in window.open method

Question

I am trying to create a window pop up using window.open method in javascript, it works fine simply without any dynamic variable passing, but i am not getting how to pass the php variable inside the function to make it functional in another window.

Here is what i have tried so far:

<?php
   if(isset($d->retweeted_status->id_str)){
      $tweetId = $d->retweeted_status->id_str;
   } else{
      $tweetId = $d->id_str;
   }
   $myUrl = "retweetDetails.php?id=".$tweetId;
<?
<a href="javascript:;" onclick="window.open('retweetDetails.php', 'my_new_window','width=625, height=400');" class="btn btn-default twitter_button_retweets"><?php echo $d->retweet_count; ?> Retweets </a>

I want to pass this $myUrl variable as a url parameter which will reflect in popup window.

Thanks

window.open('<?=$myUrl?>'?

u_mulder
– u_mulder

2015-12-22 07:09:48 +00:00
Commented Dec 22, 2015 at 7:09 — u_mulder
– u_mulder, Commented Dec 22, 2015 at 7:09
Change <? to ?> before <a tag

Tᴀʀᴇǫ Mᴀʜᴍᴏᴏᴅ
– Tᴀʀᴇǫ Mᴀʜᴍᴏᴏᴅ

2015-12-22 07:12:18 +00:00
Commented Dec 22, 2015 at 7:12 — Tᴀʀᴇǫ Mᴀʜᴍᴏᴏᴅ
– Tᴀʀᴇǫ Mᴀʜᴍᴏᴏᴅ, Commented Dec 22, 2015 at 7:12

void · Accepted Answer · 2015-12-22 07:10:33Z

2

<a href="javascript:;" onclick="window.open('<?php echo $myUrl; ?>', 'my_new_window','width=625, height=400');" class="btn btn-default twitter_button_retweets"><?php echo $d->retweet_count; ?> Retweets </a>

answered Dec 22, 2015 at 7:10

void

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Comments

rahul · Accepted Answer · 2015-12-22 07:11:19Z

0

    <?php
   if(isset($d->retweeted_status->id_str)){
      $tweetId = $d->retweeted_status->id_str;
   } else{
      $tweetId = $d->id_str;
   }
   $myUrl = "retweetDetails.php?id=".$tweetId;
<?
<a href="javascript:;" onclick="window.open('<?php echo $myUrl; ?>', 'my_new_window','width=625, height=400');" class="btn btn-default twitter_button_retweets"><?php echo $d->retweet_count; ?> Retweets </a>

answered Dec 22, 2015 at 7:11

rahul

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