Pass data to gnuplot

Question

I have this bash script:

#!/bin/bash

foo=42
./test.gp

And this is the gnuplot script (test.gp):

#!/usr/bin/gnuplot

set grid
set title "This is the title (`echo $foo`)"

set terminal png large
set output "/tmp/test.png"
set samples 50, 50
plot [-10:10] sin(x)

I'm led to believe that this should display the title as This is the title (42). But it doesn't. The resulting image looks like this: Also I want to

plot [-10:10] sin(x + `echo $foo`)

But that results in an error:

plot [-10:10] sin(x+)
                    ^
"./test.gp", line 9: invalid expression

I use gnuplot 4.6.

EDIT: moved solution to separate answer as requested in the comments.

See stackoverflow.com/q/12328603/2604213 for several possibilities. — Christoph
– Christoph, Commented Jan 1, 2016 at 10:51
Have you tried putting export foo=42 in your bash script? Also foo=42 ./test.gp works fine. And the solution given in the edited question is also given in the duplicate. — Christoph
– Christoph, Commented Jan 2, 2016 at 17:57
Marking your edit as "Added solution" to a question seems to be not a proper way to close the question as it was reopened by 5 respected men. Move your "EDIT" to an answer below. — John_West
– John_West, Commented Jan 3, 2016 at 0:00

Community · Accepted Answer · 2017-05-23 11:59:52Z

0

I tried suggestions given here but they did not appear to work for me. (Although I've been advised the solution provided below is actually mentioned there aswell).

I found that changing the script to:

#!/bin/bash


foo=42
gnuplot -e "foo='${foo}'" ./test.gp

works better. Also the GNUPLOT script becomes more readable:

#!/usr/bin/gnuplot

set grid
set title "This is the title (".foo.")"

set terminal png large
set output "/tmp/test.png"
set samples 50, 50
plot [-10:10] sin(x + foo)

edited May 23, 2017 at 11:59

CommunityBot

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answered Jan 3, 2016 at 8:07

Mausy5043

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