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I am trying to combine the set variable $jstep_optionx with $count where x is the number within the count as $jstep_option.$count, however the only output is $count as the number.

Example as per below:

<?
$jstep_choice = 'Choice';
$jstep_options = '2';
$jstep_option1 = 'Option1';
$jstep_option2 = 'Option2';
?>

<? if ( $jstep_type == 'Choice' ) { $count = 1; $options = $jstep_options; ?>
<table class='choice'>
 <tr>
  <? while ( $count <= $options ) : $choice = $jstep_option.$count; print "<td align=center><a href=?choice=".$count.">".$choice."</a></td>"; $count++; endwhile; ?>
 </tr>
</table>
<? } ?>

Output is: a TD with 1 and a TD with 2

The output should be: a TD with Option11 and a TD with Option22

Cheers.

Improve this question
4
  • 2
    Possible duplicate of variable variables Commented Apr 12, 2016 at 3:52
  • 2
    replace your $choice = $jstep_option.$count; by $choice = "jstep_option$count";$choice = $$choice.$count; Commented Apr 12, 2016 at 3:53
  • 3
    $choice = ${'jstep_option'.$count}.$count; see php.net/manual/en/language.variables.variable.php Commented Apr 12, 2016 at 3:55
  • Roullie's solution worked as: $choice = "jstep_option$count";$choice = $$choice; - The count at the end was not required, I did make a typo there, but hey the concept was understood, much thanks Roullie and Sean for the assist. Commented Apr 12, 2016 at 6:49
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