Bash script to process all files in folder and save all output in different folder with same file names?

Question

I am writing a script to change size of svg images. Here is what I am trying

#!/bin/bash
for file in *
do
  rsvg-convert "$file" -w 160 -h 160 -f svg -o `echo $i | sed -e 's/svg$/new.svg/'`
done

But this is not working.

Krzysztof Krasoń · Accepted Answer · 2016-07-18 07:10:45Z

2

Use bash substitition directly (${file%.svg} will remvoe .svg from the end of file variable):

#!/bin/bash
mkdir -p folder
for file in *
do
  rsvg-convert "$file" -w 160 -h 160 -f svg -o folder/${file%.svg}new.svg 
done

answered Jul 18, 2016 at 6:57

Krzysztof Krasoń

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4 Comments

^ for a solution with Bash substitution !

Thanks for your prompt answer but I want same file names saved in different folder

@Sid It would be good to mention that in the question, I added that the answer

@krzyk apologies for not being clear. I tried to convey it in question heading but should have explained it in description also