How to loop through all files in dir, run script, and write them into matching files in other dir

Question

I have files in a directory:

mkdir in_dir
echo 'a' > in_dir/file1.txt
echo 'b' > in_dir/file2.txt
echo 'c' > in_dir/file3.txt

mkdir out_dir

I have a command that takes input from files using < and writes output to a new file with >. I want to run it on all files in in_dir and write the output to out_dir under a matching file name.

This does the first part, runs a (dummy) command on each file.

#!/bin/zs
for file in in_dir/*;
(cat $file ; echo '1')

I'd like to have 'file1.txt' in out_dir with the content 'a1', 'file2.txt' with 'b1' etc.

echo "$(cat $file)1" > "out_dir/$file"

Raman Sailopal
– Raman Sailopal

2021-02-03 19:48:53 +00:00
Commented Feb 3, 2021 at 19:48 — Raman Sailopal
– Raman Sailopal, Commented Feb 3, 2021 at 19:48
what is the content of out_dir/file1.txt? a or a1?

Aven Desta
– Aven Desta

2021-02-03 20:19:55 +00:00
Commented Feb 3, 2021 at 20:19 — Aven Desta
– Aven Desta, Commented Feb 3, 2021 at 20:19
a1, I acknowledge that this wasn't very clear

petyar
– petyar

2021-02-04 09:21:17 +00:00
Commented Feb 4, 2021 at 9:21 — petyar
– petyar, Commented Feb 4, 2021 at 9:21

Mara Clementine · Accepted Answer · 2021-02-03 22:23:16Z

1

You have yourscript which process the information if I understood well. And you can make another script as follow:

#!/bin/bash

IFS=$'\n'

for i in `ls -1 ./dir_in` ; do
    ./yourscript "$(cat ./dir_in/$i)" > ./dir_out/$i
done

unset IFS

Don't forget to take this script chmod +x permission.

edited Feb 3, 2021 at 22:23

answered Feb 3, 2021 at 20:10

Mara Clementine

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