So I have an array of object which looks like this:
var myArray = [{priority : "low"}, {priority: "critical"}, {priority: "high"}]
I need to sort in this way: 1)Critical, 2) High and 3) Low.
how can this be done?
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At starters, read Array.sort at MDN.Teemu– Teemu2016-08-26 20:56:31 +00:00Commented Aug 26, 2016 at 20:56
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2 Answers
I suggest to use an object for the storing of the sort order.
If you need a default value for sorting, you could use a value for sorting unknown priority to start or to the end.
var sort = ['critical', 'high', 'low'],
defaultValue = Infinity,
sortObj = {},
myArray = [{ priority: "unknown" }, { priority: "low" }, { priority: "critical" }, { priority: "high" }];
sort.forEach(function (a, i) { sortObj[a] = i + 1; });
myArray.sort(function (a, b) {
return (sortObj[a.priority] || defaultValue) - (sortObj[b.priority] || defaultValue);
});
console.log(myArray);3 Comments
Jeka
this should have been accepted answer from beginning thanks
georg
Premature optimizations....
(a, b) => sort.indexOf(a.priority) - sort.indexOf(b.priority) would be much simpler.
Nina Scholz
@georg, i am not a fan of
indexOf.Use an object that maps priority names to numbers, then sort based on that.
var priorities = {
low: 0,
high: 1,
critical: 2
};
var myArray = [{
priority: "low"
}, {
priority: "critical"
}, {
priority: "high"
}]
myArray.sort(function(a, b) {
return priorities[b.priority] - priorities[a.priority];
});
console.log(myArray);
