I am writing currently a little parser for JSON documents.
UTF characters can be represented as \u0628.
How can I turn the string \u0628 into a real Java character?
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2 Answers
you can use a piece of code like this:
String str = myString.split(" ")[0];
str = str.replace("\\","");
String[] arr = str.split("u");
String text = "";
for(int i = 1; i < arr.length; i++){
int hexVal = Integer.parseInt(arr[i], 16);
text += (char)hexVal;
}
or you can use Apache Commons Lang:
import org.apache.commons.lang.StringEscapeUtils;
@Test
public void testUnescapeJava() {
String sJava="\\u0048\\u0065\\u006C\\u006C\\u006F";
System.out.println("StringEscapeUtils.unescapeJava(sJava):\n" + StringEscapeUtils.unescapeJava(sJava));
}
output:
StringEscapeUtils.unescapeJava(sJava):
Hello
Comments
You can parse the bytes using the UTF_16 charset:
E.g.
byte[] data = {0x06, 0x28};
String string = new String(data, StandardCharsets.UTF_16);
You could find the escapes using a regex
private static Pattern ESCAPE_PATTERN = Pattern.compile("\\\\u([0-9a-fA-F]{2})([0-9a-fA-F]{2})");
public static String replaceCharEscapes(String input) {
Matcher m = ESCAPE_PATTERN.matcher(input);
if (!m.find()) {
return input;
}
StringBuilder outputBuilder = new StringBuilder(input.subSequence(0, m.start()));
int lastEnd = m.end();
outputBuilder.append(getChar(m));
while (m.find()) {
outputBuilder.append(input.subSequence(lastEnd, m.start()))
.append(getChar(m));
lastEnd = m.end();
}
if (lastEnd != input.length()) {
outputBuilder.append(input.subSequence(lastEnd, input.length()));
}
return outputBuilder.toString();
}
private static String getChar(Matcher m) {
return new String(new byte[] {
Byte.parseByte(m.group(1), 16),
Byte.parseByte(m.group(2), 16),
});
}
example:
replaceCharEscapes("\\u0043:\\\\u0050\\u0072\\u006f\\u0067\\u0072\\u0061\\u006ds")
returns C:\Programs
