I would like to be able to convert a raw UTF-8 string to a Hex string. In the example below I've created a sample UTF-8 string containing 2 letters. Then I'm trying to get the Hex values but it gives me negative values.
How can I make it give me 05D0 and 05D1
String a = "\u05D0\u05D1";
byte[] xxx = a.getBytes("UTF-8");
for (byte x : xxx) {
System.out.println(Integer.toHexString(x));
}
Thank you.
Don't convert to an encoding like UTF-8 if you want the code point. Use Character.codePointAt.
For example:
Character.codePointAt("\u05D0\u05D1", 0) // returns 1488, or 0x5d0
new String(bytes, "UTF-8") and then use Character.codePointAt(...).toHexString() to get the hex representation.
Character.codePointAt doesn't have a toHexString method, it returns an integer. Can you please give me complete example? ThanksSystem.out.println(Integer.toHexString(Character.codePointAt("\u05D0", 0))) will print out 5d0. If you want to pad it with zeros on the left, try System.out.printf("%08x", Character.codePointAt("\u05D0", 0)) which prints 000005d0.Negative values occur because the range of byte is from -128 to 127. The following code will produce positive values:
String a = "\u05D0\u05D1";
byte[] xxx = a.getBytes("UTF-8");
for (byte x : xxx) {
System.out.println(Integer.toHexString(x & 0xFF));
}
The main difference is that it outputs x & 0xFF instead of just x, this operation converts byte to int, dropping the sign.
