How to use regex to find strings from string with multiple brackets?

Question

I am fetching and looping on strings which can have one brackets or multiple as shown below. I want the strings inside the last bracket.

strOne = "This contains (18xp) (23lo) (SerialA)"
strTwo = "This contains (jxp) (SerialB)"
strThree = "Some strings (randomA9)"

I tried to use below code but it only capture first:

regFormat = '(\([A-Z0-9]+\))'
pathReg = re.compile(regFormat)
findr = re.findall(pathReg , strOne)
print(findr)

RESULT : ['(18xp)']

If you expect 1 single match, why use re.findall? Use re.search. Are those parentheses always at the end of the string? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Nov 24, 2016 at 13:25

malutki5200 · Accepted Answer · 2016-11-24 13:18:08Z

1

You have to use a regexp signs indicating the start and the end of the line.
Try:

'^.*?(\([A-Z0-9]+\))$'

answered Nov 24, 2016 at 13:18

malutki5200

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1 Comment

The ^.*? is redundant, r'$[^()]+$$' should be enough.