PHP array of non-primitive class as function parameter

Question

I am wondering (if possible) how you would declare an array of non-primitive class as a function parameter. For example

<?php
class C {}

function f(array C $c) {
    /* use $c[1], $c[2]... */
}

There's no need to declare any type for $c, you can directly do function f($c){ ... }, given that $c is an array of Class C objects. — Rajdeep Paul
– Rajdeep Paul, Commented Jan 22, 2017 at 18:26
No way for this. Or create a class like CCollection which will store collection of C objects — u_mulder
– u_mulder, Commented Jan 22, 2017 at 18:26
you dont need to add "array" in your parameter. All you need to do is add what type of object you are passing, in this case is class C as so: function f(C $c) { .. } — CodeGodie
– CodeGodie, Commented Jan 22, 2017 at 18:36

u_mulder · Accepted Answer · 2017-01-22 18:50:56Z

1

Main fact - currently you can't type hint argument as array of something.

So you options are:

// just a function with some argument, 
// you have to check whether it is array 
// and whether each item in this array has type `C`
function f($c) {} 

// function, which argument MUST be array.
// if it is not array - error happens
// you still have to check whether 
// each item in this array has type `C`
function f(array $c) {} 

// function, which argument of type CCollection
// So you have to define some class CCollection
// object of this class can store only `C` objects
function f(CCollection $c) {} 

// class CCollection can be something like
class CCollection 
{
    private $storage = [];

    function addItem(C $item)
    {
        $this->storage[] = $item;
    }

    function getItems()
    {
        return $this->storage;
    }
}

answered Jan 22, 2017 at 18:50

u_mulder

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1 Comment

Philipp Over a year ago

PHP7.1 supports an iterable type hint: wiki.php.net/rfc/iterable

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