Pass array as function parameters for class constructor

Question

How can I pass an array as constructor parameters in class instantiation?

abstract class Person {

    protected function __construct(){

    }

    public static final function __callStatic($name, $arguments){
        return new $name($arguments);
    }

}

class Mike extends Person {

    protected function __construct($age, $hobby){
        echo get_called_class().' is '.$age.' years old and likes '.$hobby;
    }
}


// =============================================

Person::Mike(15, 'golf');

This should output

Mike is 15 years old and likes golf

But I get second parameter missing in Mike's constructor, because both parameters from __callStatic are sent as array into $age. My question is how can I send them as parameters instead of array?

It's been a while since I worked with PHP but shouldn't you be using 2x_ in the constructor instead of 1? — Jonast92
– Jonast92, Commented Sep 12, 2014 at 15:48

Community · Accepted Answer · 2023-11-17 20:24:09Z

2

You can use Reflection for this:

public static function __callStatic($name, $arguments){
    $reflector = new ReflectionClass($name);
    return $reflector->newInstanceArgs($arguments);
}

edited Nov 17, 2023 at 20:24

CommunityBot

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answered Sep 12, 2014 at 15:51

Jeff Lambert

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Comments

Community · Accepted Answer · 2023-11-17 19:40:22Z

1

Use call_user_func_array(), https://www.php.net/manual/en/function.call-user-func-array.php and a factory method:

class Mike extends Person {

    public static function instantiate($age, $hobby) {
        return new self($age, $hobby);
    }
    protected function __construct($age, $hobby){
        echo get_called_class().' is '.$age.' years old and likes '.$hobby;
    }
}

And then make a Mike like so:

abstract class Person {

    protected function __construct(){

    }

    public static final function __callStatic($name, $arguments){
        return call_user_func_array(array($name, 'instantiate'), $args);
    }

}

edited Nov 17, 2023 at 19:40

CommunityBot

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answered Sep 12, 2014 at 15:51

Schlaus

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3 Comments

php_nub_qq Over a year ago

I can't do that. I need to be able to call Person::Mike()

Schlaus Over a year ago

This does exactly that.

php_nub_qq Over a year ago

but then I have to implement instantiate into all classes, this is not smart.

Machavity · Accepted Answer · 2014-09-12 15:57:34Z

0

You're using the static scope resolutor wrong

Person::Mike(15, 'golf');

That would mean you have a static method Mike inside the class Person and you're calling it statically.

Instead, you want to instantiate Mike

$mike = new Mike(15, 'golf');

If you want to call static things from Person, because Mike extends it, Mike can also call it statically.

Mike::staticMethod($args);

edited Sep 12, 2014 at 15:57

answered Sep 12, 2014 at 15:51

Machavity♦

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2 Comments

php_nub_qq Over a year ago

No I don't want to do that. I have a class Person that can return instances of people classes, I explicitly don't want to be able to call people classes constructors, that's why they are protected.

Machavity Over a year ago

I added something to better deal with your static needs

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