Php url parameter error

Question

I am getting error.

url.com/test.php?id=123&id2=456

This is my get.php

<?php

$id = $_GET['id'];
$id2 = $_GET['id2'];

?>

I am getting this error for 2nd parameter

instead of & url getting &

Error

[23-Feb-2017 03:45:00 UTC] PHP Notice:  Undefined index: id2 in /home/xxxx/public_html/url.com/get.php on line 4

you url_encode() and url_decode() function for this

Gulshan S
– Gulshan S

2017-02-23 04:45:57 +00:00
Commented Feb 23, 2017 at 4:45 — Gulshan S
– Gulshan S, Commented Feb 23, 2017 at 4:45
example please sir

Vince
– Vince

2017-02-23 04:46:46 +00:00
Commented Feb 23, 2017 at 4:46 — Vince
– Vince, Commented Feb 23, 2017 at 4:46
search in google. you will find example

prakash tank
– prakash tank

2017-02-23 04:54:28 +00:00
Commented Feb 23, 2017 at 4:54 — prakash tank
– prakash tank, Commented Feb 23, 2017 at 4:54
Read How to ask on Stackoverflow before posting a query

Prasad
– Prasad

2017-02-23 05:41:21 +00:00
Commented Feb 23, 2017 at 5:41 — Prasad
– Prasad, Commented Feb 23, 2017 at 5:41

Gulshan S · Accepted Answer · 2017-02-23 04:59:36Z

1

  try this..
   url.com/test.php?id=" . urlencode($id) . "&id2=" . urlencode($id2);

 Decode:

  $id= urldecode($_GET['id']);
  $id2= urldecode($_GET['id2']);

edited Feb 23, 2017 at 4:59

Gulshan S

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answered Feb 23, 2017 at 4:50

Dee_wab

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3 Comments

Vince Over a year ago

header("Location: get.php?fbid=".urlencode($id)."&fname=".urlencode($id2).""); Not working still I am getting error.

Vince Over a year ago

error is in & char. second parameter is not getting

Dee_wab Over a year ago

@vience try this code i personaly test hope it should work - $id=2; $test=3; <a href='./test.php?id=<?php echo urlencode($id); ?>&test1=<?php echo urlencode($test); ?>'>test</a> test.php <?php echo $id= urldecode($_GET['id']); echo $test= urldecode($_GET['test1']); ?>

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