Split string between characters with Python regex

Question

I'm trying to split the string:

> s = Ladegårdsvej 8B7100 Vejle

with a regex into:

[street,zip,city] = ["Ladegårdsvej 8B", "7100", "Vejle"]

s varies a lot, the only certain part is that there are always 4 digits in the zip and a whitespace afterwards. My idea is thus to "match from the right" on 4 digits and a whitespace to indicate that the string should be split at that point in the string.

Currently I'm able to get street and city like this:

> print re.split(re.compile(r"[0-9]{4}\s"), s)
["Ladegårdsvej 8B", "Vejle"]

How would I go about splitting s as desired; in particular, how to do it in the middle of the string between the number in street and zip?

Would all strings have the same overall format as that string, cause then you could just split it on whitespace cause that seems to be a delimiter between the three — Professor_Joykill
– Professor_Joykill, Commented Jul 24, 2017 at 12:21
@Professor_Joykill: There is no whitespace between street & zip. — Scott Hunter
– Scott Hunter, Commented Jul 24, 2017 at 12:22
@Professor_Joykill please note that OP wants to put 7100 rather than 8B7100 into zip. — Błotosmętek
– Błotosmętek, Commented Jul 24, 2017 at 12:22
See ideone.com/dmyo6b, you may match and capture the parts. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 24, 2017 at 12:23

tobias_k · Accepted Answer · 2017-07-24 12:24:31Z

9

You can use re.split, but make the four digits a capturing group:

>>> s = "Ladegårdsvej 8B7100 Vejle"
>>> re.split(r"(\d{4}) ", s)
['Ladegårdsvej 8B', '7100', 'Vejle']

From the documentation (emphasis mine)

Split string by the occurrences of pattern. If capturing parentheses are used in pattern, then the text of all groups in the pattern are also returned as part of the resulting list. If maxsplit is nonzero, at most maxsplit splits occur, and the remainder of the string is returned as the final element of the list.

answered Jul 24, 2017 at 12:24

tobias_k

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Scott Hunter · Accepted Answer · 2017-07-24 12:24:19Z

1

Once you have street, getting zip is trivial:

zip = s[len(street):len(street)+4]

answered Jul 24, 2017 at 12:24

Scott Hunter

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Rohit-Pandey · Accepted Answer · 2017-07-26 03:22:03Z

0

Here is the solution for your problem.

# -*- coding: utf-8 -*-
import re
st="Ladegårdsvej 8B7100 Vejle"
reg=r'([0-9]{4})'
rep=re.split(reg,st)
print rep

Solution for other test cases as provided by RasmusP_963 sir.

# -*- coding: utf-8 -*-
import re
st="Birkevej 8371900 Roskilde"
print re.split(r"([0-9]{4}) ",st)

edited Jul 26, 2017 at 3:22

answered Jul 25, 2017 at 9:55

Rohit-Pandey

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1 Comment

RasmusP_963 Over a year ago

That won't work, because there could be a street address with long house number without letters (e.g. Birkevej 8371900 Roskilde), so I need to include the whitespace afterwards to ensure it matches on the last four numbers (the zip).

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