Split string using regular expression in python

Question

I have such string

Sale: \t\t\t5 Jan \u2013 10 Jan

I want to extract the start and the end of the sale. Very straightforward approach would be to make several spilts, but I want to that using regular expressions. As the result I want to get

start = "5 Jan"
end = "10 Jan"

Is it possible to do that using regex?

@user202729 thanks, what is the pattern? I'm a bit confused about these unicode symbol — Daniel Chepenko
– Daniel Chepenko, Commented Mar 11, 2018 at 13:16
Will the start always be the first date and the end always the second date? — Sweeper
– Sweeper, Commented Mar 11, 2018 at 13:17

Rakesh · Accepted Answer · 2018-03-11 13:17:35Z

3

This should help.

import re
s = "Sale: \t\t\t5 Jan \u2013 10 Jan"
f = re.findall(r"\d+ \w{3}", s)
print f

Output:

['5 Jan', '10 Jan']

answered Mar 11, 2018 at 13:17

Rakesh

82.9k17 gold badges85 silver badges122 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Austin · Accepted Answer · 2018-03-11 13:39:30Z

1

This may not be an optimised one but works assuming the string pattern remains the same.

import re
s = 'Sale: \t\t\t5 Jan \u2013 10 Jan'
start, end = re.search(r'Sale:(.*)', s).group(1).strip().replace('\u2013', ',').split(', ')

# start <- 5 Jan
# end <- 10 Jan

answered Mar 11, 2018 at 13:39

Austin

26.1k4 gold badges28 silver badges52 bronze badges

Collectives™ on Stack Overflow

Split string using regular expression in python

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related