Python run multiple commands after assert

Question

How do I run multiple commands after calling an assert statement? For example, here's what I would like to do (without using assert):

x = False
if x != True:
    my_func()
    raise ValueError("My statement")

This does exactly what I want, but it seems more Pythonic to use assert in this case. I cannot figure out how to do multiple things after calling assert. Here's what I'm trying to do (but with incorrect syntax):

x = False
assert x == True, my_func() "My statement"

Why would it be more Pythonic to use assert? On the contrary, using exceptions is the right way. — Daniel Roseman
– Daniel Roseman, Commented Jan 3, 2018 at 11:48
It just seemed like a natural place to use assert, but I guess not. I'll use the exception then. — jss367
– jss367, Commented Jan 3, 2018 at 11:50
I would suggest using a try statement here, in which case you can do proper exception handling and execute multiple commands if something goes right or wrong. — 1313e
– 1313e, Commented Jan 3, 2018 at 11:53
Could you try with assert x == True, [my_func(), "My statement"][1] — user459872
– user459872, Commented Jan 3, 2018 at 11:59

user459872 · Accepted Answer · 2018-01-03 12:03:55Z

1

You could do

assert x == True, [my_func(), "My statement"][1]

DEMO

def my_func():
    print("my function")

x = False
assert x == True, [my_func(),  "My statement"][1]

OUTPUT

my function
Traceback (most recent call last):
  File "C:/Users/abdul.niyas/AppData/Local/Programs/Python/Python36-32/a.py", line 5, in <module>
    assert x == True, [my_func(),  "My statement"][1]
AssertionError: My statement

answered Jan 3, 2018 at 12:03

user459872

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1 Comment

Jeronimo Over a year ago

Clever solution. But in my opinion still a lot harder to read then the classic if not x: ....

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