I have a Integer array as follows.
Integer[] nums = new Integer[]{1,2,3};
Integer inputNum = 3;
I would like to check if 3 is present here.
Was trying to use the below code, but it doesn't accept, Integer[].
IntStream.of(nums).anyMatch(num -> num == inputNum);
IntStream java.util.stream.IntStream.of(int... values)
Is there any better approach with Java 8?
You currently have an Integer[] therefore you can utilise Stream.of instead of IntStream.of.
IntStream.of only takes primitive integers whereas Stream.of is used for reference types.
boolean isPresent = Stream.of(nums).anyMatch(num -> Objects.equals(num, inputNum));
but I prefer to use Arrays.stream in this case instead of the XXX.of methods as in the ideal world you should only use them when you're going to provide explicit values.
boolean isPresent = Arrays.stream(nums).anyMatch(num -> Objects.equals(num, inputNum));
Arrays.asList(nums).contains(inputNum) is not only shorter but clearer in intent.
num==numwill match everything in the stream.Integer[]I reckonArrays.asList(nums).contains(inputNum)is actually neater and likely more performant. This is a case of "when you have a hammer, everything looks like a nail".