Passing java script value to another page

Question

I have a page here prompt get an input and stores in a variable called ans,i need to pass this value to y.php

<script type="text/javascript">
function s()
{
var ans = prompt("Name your query?","");
}
</script>
<input type="image" src="images/savn.jpg" onclick="s();" />
<form method=post" action="y.php">

below here it has some text boxes so,i need this values also to be posted to y.php

I am struck.Can,any one take me further to next step?

Neil · Accepted Answer · 2011-02-03 14:34:10Z

2

Place on your page:

<input type="hidden" id="ans" name="ans" value="" />

Following the line var ans = prompt("Name your query?","");, add the line:

document.getElementById("ans").value = ans;

This should guarantee that you can access the variable "ans" on the page y.php as variable $_POST['ans'].

answered Feb 3, 2011 at 14:34

Neil

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7 Comments

qahjkj Over a year ago

I am getting this [object HTMLInputElement] in y.php.I did not get prompt input.

Neil Over a year ago

I'm assuming the function s gets run first, so presumably you'd click on the image first and then submit? You should see some sort of prompt.

qahjkj Over a year ago

@Neil:I need to save only after two text boxes.How do i do it?

Neil Over a year ago

Add a function testValid which checks if values have been inserted: if(document.getElementById('textbox1').value.length == 0) return false; and add that method in the event onsubmit="return testValid()" in the form tag. You can move the prompt for ans after you do the validation so it only asks when you've inserted valid values. Hope that helps.

qahjkj Over a year ago

@neil:i have a textb enter data and text box2 enter data so here above prompt should get ip only if 2 text box values are present

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btilly · Accepted Answer · 2011-02-03 14:32:18Z

1

Create a hidden form element and set it.

<script type="text/javascript">
function s()
{
  document.getElementById('ans').value = prompt("Name your query?","");
}
</script>
<input type="image" src="images/savn.jpg" onclick="s();" />
<input type="hidden" name="ans" id="ans" />
<form method=post" action="y.php">

Now when you submit the form, the form variable will be submitted back.

answered Feb 3, 2011 at 14:32

btilly

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