PHP How to get function parameters, when function is passed as parameter

Question

I want to do something like this:

function func($callback) {
    $result = $callback(???);    // $callback must be called here
    //...
}

//...
func(function(['foo' => 'buu']) {
    $a = func_get_arg(0);

    // do something with $a and return something...    
    return $something;       
})

It is possible in php?

I can do something like below, but this is not what I want to do:

function func($args, $callback) {
    $result = $callback($args);
    //...
}

func(['foo' => 'boo'], function($args) {
     $a = $args; // etc.
})

It seems to me like ['foo' => 'boo'] is being set where the callback is set, so why not just assign $a to ['foo' => 'boo'] in the callback instead of trying to use func_get_arg(0);? — Ethan
– Ethan, Commented Oct 5, 2018 at 9:39

Cid · Accepted Answer · 2018-10-05 09:54:53Z

3

I use anonymous function this ways :

$mySuperFunction = function($arg)
{
    echo ("Hello " . $arg);
};

function AnotherFunction($args)
{
    echo ("Another hello " . $args);
}

function WrappingAnonymous($callback, $args)
{
    $callback($args);
}

function WrappingAnonymousWithoutArgs($callback)
{
    $callback();
}

WrappingAnonymous($mySuperFunction, "World");
WrappingAnonymous("AnotherFunction", "World");
WrappingAnonymous(function($someArgs)
{
    echo "Yet another Hello " . $someArgs;
}, "World");


WrappingAnonymousWithoutArgs(function($someArgs = "World")
{
    echo "Now, a 4th other Hello " . $someArgs;
});

Outputs :

Hello World

Another hello World

Yet another Hello World

Now, a 4th other Hello World

edited Oct 5, 2018 at 9:54

answered Oct 5, 2018 at 9:39

Cid

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