I have a function:
function passParams($a, $b = null, $c)
{
echo "<pre>"; var_dump($a); echo "<br/>"; die('123');
}
and I want to call it like this:
passParams($a = 10, $c = 1);
How do I have to?
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3 Answers
Try this...
<?php
function addFunction($num1, $num2,$test=NULL)
{
$sum = $num1 + $num2;
echo "Sum of the two numbers is : $sum";
}
addFunction(10, 20,NULL);
?>
answered Jul 9, 2015 at 8:42
Deenadhayalan Manoharan
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1 Comment
Hoang NK
yes. I know that, but now I want to call the function with 2 params, the rest of param will be set default value when it isn't passed
Define parameters with default values at the end of function arguments.
function passParams($a, $c, $b = null)
{
echo "<pre>"; var_dump($a); echo "<br/>"; die('123');
}
And call it by -
passParams(10, 1);
Then -
$a will be - 10
$b will be - NULL
$c will be - 1
2 Comments
Hoang NK
Thanks. so we have to call by order of parameters?
Sougata Bose
Yup. The order will set them accordingly.
You can always call like this:
passParams(10, NULL, 1);
This way 2nd parameter will remain its default value as specified in the function
1 Comment
Sougata Bose
I want to call the function with 2 params, the rest of param will be set default value when it isn't passed
