When Defining a constructor in a class I initially had something like:
public function __construct(MyClass $class){ ... }
However I wanted to be able to accept an array of MyClasses, how could you define this in your constructor?
Cheers
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3 Answers
Not strictly typecasting, but will enforce what you're looking for.
public function __construct(array $classes){
foreach($classes as $inst){
if(!($inst instanceof ClassName)){
trigger_error('Array of objects passed to constructor must contain instances of ClassName', E_USER_ERROR);
}
//perform actions
}
}
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You can only specify one type this way.
So, either an object, instance of MyClass :
public function __construct(MyClass $class){ ... }
Or an array :
public function __construct(array $data){ ... }
But you cannot specify your method only accepts an array of MyClass -- which means you'll have to check by yourself what kind of data are into the array your receive, in the second case.
1 Comment
Raffael
or nothing: public function __construct($class){ ... }
Cast $class as an array.
public function __construct($class = array()) { }
or
public function __construct(array $class) { }
further:
foreach($class as $instance) {
if(!$instance instanceof MyClass) { return false; }
}
Comments
