php function with variable and array

Question

I am trying to create a PHP function with 2 parameters. One parameter is a variable and the second is an array like this

<?php
function Myfunction($variable, $array=array()){
foreach($array as $item){
        echo $variable;
        echo  $item;
    }
}
?>

I want a call like this:

<?php
Myfunction(blue, 1,3,6,10,5);
?>

"blue" is the variable "numbers" insert in an array.

I tried something but it does not work.

Who can help me with this?

Maybe this Myfunction('blue', array(1,3,6,10,5)); will help. — Zhorov
– Zhorov, Commented Mar 8, 2019 at 22:07
Simple, just call it like this MyFunction(blue, [1,3,6,10,5]); — toh19
– toh19, Commented Mar 8, 2019 at 22:10

Miroslav Glamuzina · Accepted Answer · 2019-03-08 22:10:40Z

1

Well, there are two possibilities:

You can wrap your values in an array (ie: []), which I believe is what you intended:

Myfunction(blue, [1,3,6,10,5]);

Or you could take advantage of PHP's variable argument list and have your function parameters listed like so:

Myfunction($variable, ...$array);

Note the ... before $array, this signifies that this parameter will accept a variable number of arguments. Keep in mind that parameter using ... must be the last parameter in your argument list. With this, you may call your function like so:

Myfunction(blue, 1,3,6,10,5);

Hope this helps,

answered Mar 8, 2019 at 22:10

Miroslav Glamuzina

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1 Comment

Jop Over a year ago

Thanks Miroslav for the solution! I made the function with the advanced option :)

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