function with array variable

Question

How do I pass an array through a function, for example:

$data = array(
    'color'  => 'red',
    'height' => 'tall'
);

something($data);

function something($data) {
    if ($data['color'] == 'red') {
        // do something
    }
}

how can I get the function to recognize $data[color] and $data[height]?

Do you mean you need the function to be able to modify the array? — user180100
– user180100, Commented Jun 8, 2010 at 6:15
I need the function to understand that $data[color] equals red. So that I can use: if ($data[color] == 'red') { do something } inside the function — CruisinCosmo
– CruisinCosmo, Commented Jun 8, 2010 at 6:17
I edited the post so that it hopefully makes a bit more sense. Does what I have look correct? — CruisinCosmo
– CruisinCosmo, Commented Jun 8, 2010 at 6:23
Quotes are missing around color in the if. Could be your problem. — user180100
– user180100, Commented Jun 8, 2010 at 6:27

Dan Soap · Accepted Answer · 2010-09-16 11:47:14Z

1

Sometimes the easiest answer is the right one:

$data = array(
    'color'  => 'red',
    'height' => 'tall'
);


function something($data) {
    if ($data['color'] == 'red') {
        // do something
    }
} 

something($data);

Arrays don't need a special handling in this case, you can pass any type you want into a function.

edited Sep 16, 2010 at 11:47

answered Jun 8, 2010 at 6:25

Dan Soap

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Comments

deceze · Accepted Answer · 2010-06-08 06:31:16Z

1

This works:

$data = array('color'  => 'red', 'height' => 'tall');

function something($data) {
    if ($data['color'] == 'red') {
        // do something
    }
}

something($data);

As remark, you need to quote your strings: $data['color'].

answered Jun 8, 2010 at 6:31

deceze♦

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Comments

Young · Accepted Answer · 2010-06-08 06:33:50Z

0

Maybe you need to make some validations to the parameter to make the function more reliable.

function something($data)
{
    if(is_array(data) and isset($data['color']))
    {
         if($data['color'] == 'red')
         {
            //do your thing
         }
    }
    else
    {
         //throw some exception
    }
}

answered Jun 8, 2010 at 6:33

Young

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